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Nostrana [21]
3 years ago
8

Based on the oxidation states of the atoms in this reaction, answer the questions. Fe(0) + O2(0) → Fe2(3+)O3(2-) How many electr

ons does the iron half-reaction lose? How many electrons does the oxygen half-reaction gain?
Chemistry
2 answers:
Oliga [24]3 years ago
6 0
Half reaction 1: 2Fe° → Fe₂³⁺ + 6e⁻ /×2.
4Fe° → 2Fe₂³⁺ + 12e⁻.
Iron is oxidized from neutral charge (0) to oxidation number +3, one iron lose three electrons, two irons lose six electrons and four irons twelve electrons.
Half reaction 2: 12e⁻ + 3O₂ → 2O₃²⁻ 
Oxygen is reduced from neutral chage to oxidation number -2, one oxygen gain two electrons, six oxygens gain twelve electrons.
Balanced chemical reaction: 4Fe + 3O₂ → 2Fe₂O₃.
aalyn [17]3 years ago
6 0

Answer:

The iron half-reaction loses 12.

The oxygen half reaction gains 12.

The total number of electrons that are moved in this oxidation-reduction reaction is 12.

Explanation:

Edge 2020

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Answer: The space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

Explanation:

Given: V_{1} = 250 mL,    P_{1} = 800 torr,     T_{1} = 50^{o}C

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Formula used is as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}

Substitute the values into above formula as follows.

\frac{P_{1}V_{1}}{T_{1}} = \frac{P_{2}V_{2}}{T_{2}}\\\frac{800 torr \times 250 mL}{50^{o}C} = \frac{400 torr \times V_{2}}{25^{o}C}\\V_{2} = 250 mL

Thus, we can conclude that space occupied by the gas at 400 torr and 25^{o}C is 250 mL.

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