Answer: Computer chips are very complex, maybe there are things insode that chemists are familiar with. Maybe they can give insight about this.
Explanation:
Fat: 1 gram = 9 calories Protein: 1 gram = 4 calories Carbohydrates: 1 gram = 4 calories Alcohol: 1 gram = 7 calories"
So, (12 g carbohydrates)*4 Cal=48 Cal; (9 g fat) *9 Cal=81 Cal; (9 g protein)*4 Cal=36 Cal
48 Cal + 81 Cal + 36 Cal = 165 Cal in one glass of milk
Answer:

Explanation:
We will need a balanced chemical equation with masses and molar masses, so, let's gather all the information in one place.
Mᵣ: 98.08 392.18
2Cr + 3H₂SO₄ ⟶ Cr₂(SO₄)₃ + 3H₂
To solve the stoichiometry problem, you must
- Use the molar mass of H₂SO₄ to convert the mass of H₂SO₄ to moles of H₂SO₄
- Use the molar ratio to convert moles of H₂SO₄ to moles of Cr₂(SO₄)₃
- Use the molar mass of Cr₂(SO₄)₃ to convert moles of Cr₂(SO₄)₃ to mass of Cr₂(SO₄)₃
a) Mass of Cr₂(SO₄)₃
(i) Mass of pure H₂SO₄

(ii) Moles of H₂SO₄

(iii) Moles of Cr₂(SO₄)₃
The molar ratio is 1 mol Cr₂(SO₄)₃:3 mol H₂SO₄

(iv) Mass of Cr₂(SO₄)₃

b) Percentage yield
It is impossible to get a yield of 485.9 g. I will assume you meant 185.9 g.

The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
<h3>What is Balanced Chemical Equation ?</h3>
The balanced chemical equation is the equation in which the number of atoms on the reactant side is equal to the number of atoms on the product side in an equation.
Now we have to write the balanced equation
C₂H₅OH + 3O₂ → 2CO₂ + 3H₂O
We can see that every 1 mole of ethanol we will get 2 mole of CO₂.
So 6.0 mol of ethanol we will get = 6.0 × 2.0
= 12 mol of CO₂
Thus from the above conclusion we can say that The number of moles of CO₂ that is produced when burning 6.0 mol of ethanol is 12 mol.
Learn more about the Balanced Chemical Equation here: brainly.com/question/26694427
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Answer:
C. 10/9 gallons
Explanation:
Given that
V= 20 gallons
Volume of ethanol = 5% of V = 0.05 x 20 = 1 gallons
Volume of the gasoline = 95 % of V = 19 gallons
Lets take x gallons of ethanol is added to achieve optimum performance.
(1+x)/(20+x) = 10 %
(1+x)/(20+x) =0.1
1+ x = 0.1 ( 20+ x)
1+ x = 2 + 0.1 x
1 = 0.9 x
x= 10 /9 gallons
So the option C is correct.
C. 10/9 gallons