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4 years ago

The pap smear is ________ percent approximate in detecting cervical carcinoma

1 answer:

5 0

Pap smear (Papanicolau smear) is a procedure that involves swabbing the endocervix (inner part of the cervix), ectocervix (outer part of the cervix), and the vaginal walls. This smear will then be fixed and then viewed through a microscope to check for atypical cells (or cancer cells). Pap smear has a 95% sensitivity so pap smear can detect cervical carcinoma 95% of the time.

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Inside each of your lungs there are tubes called bronchi. these branch into even smaller tubes much like the branches of a tree.

marishachu [46]

I think it is bronchioles.

4 0

4 years ago

Read 2 more answers

Identify four types of Green Technology used in your home

DiKsa [7]

Answer:

Types of Green Technology used in our home are the following.

1) Solar panels

2) Electric Microwave

3) Electric heater

4) Washing machine

Explanation:

Green Technology is a type of technology in which those materials are used which doesn't cause pollution in our environment. Solar panel, Electric Microwave, Electric heater and Washing machine are the examples of green technology because these machines does not pollute the environment.

8 0

4 years ago

What happens first when a bladderwort catches a

mash [69]

The answer is A, the bladderwort eats the tadpoles tail:)

7 0

3 years ago

Part C Firefly luciferase is the enzyme that allows fireflies to illuminate their abdomens. Because this light generation is an

Bumek [7]

Answer:

K = 9.620 × 10⁻⁶

Explanation:

From the given information:

Temperature T= 6° C

= (273 + 6)K

= 279 K

The correct and well presentation of the reactions are:

1. $Luciferin + O_2$ ⇆ oxyluciferin + light ΔG₁°

2. ATP ⇄ AMP + PP $_i$ ΔG₂° = -31.6 kJ/mol

The overall ΔG° = -4.80 kJ/mol

Let's first determine the ΔG₁° for the equation (1)

ΔG° = ΔG₁° + ΔG₂°

- ΔG₁° = - ΔG° + ΔG₂°

ΔG₁° = ΔG° - ΔG₂°

ΔG₁° = ( -4.80 - (-31.6) ) kJ/mol

ΔG₁° = 26.8 kJ/mol

Using the formula:

ΔG° = -RTIn K

$In \ K =\dfrac{-\Delta G^0}{RT} \\ \\ log \ K = -\dfrac{\Delta G^0}{2.303RT}$

$log \ K = -\dfrac{\Delta G_1^0}{2.303RT} \\ \\ log \ K = -\dfrac{26.8 \times 10^3 \ J/mol}{2.303\times 8.314 \ J/mol/K \times 279 \ K} \\ \\ log \ K =- 5.017$

K = antilog (-5.017)

K = 9.620 × 10⁻⁶

6 0

3 years ago

Which is considered a scientific theory?

kap26 [50]

Answer:

Explanation:

3 0

2 years ago