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3 years ago

Please help ASAP!!!!!!!!!!

Biology

2 answers:

boyakko [2]3 years ago

8 0

Greenhouse gasses, Carbon Dioxide, Water Pollution and Air Pollution and Wildfires

3241004551 [841]3 years ago

6 0

I’d say 1,2, and 5. Hope this helps.

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A mother brings a 15-month-old child to the well-baby clinic. she states the child has been taking approximately 18 to 20 oz (54

svet-max [94.6K]

A 15-month-old child, equivalent to a child of 1 year and 3 months of age, should have began weaning from bottle feeding from 6 months of age. Tooth decay or dental caries are commonly associated with prolonged bottle feeding as the sugars and other substances in milk; when drank from a teat from a bottle; prolongs the exposure of teeth to the milk, leading to overgrowth of bacteria causing dental caries.

3 0

3 years ago

Classify the sets of bones below as being part of the axial skeleton or the appendicular skeleton.

Tasya [4]

Answer:

Hello the correct answers are......

Classify the sets of bones below as being part of the axial skeleton or the appendicular skeleton.

✔ appendicular skeleton = hands and feet

✔ axial skeleton = sternum

✔ axial skeleton = skull

✔ appendicular skeleton = hips

✔ axial skeleton = ribs

✔ appendicular skeleton = shoulders

✔ appendicular skeleton = arms and legs

✔ axial skeleton = vertebral column

Explanation:

just took the test from edge

hope this helps :P

4 0

3 years ago

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22. A plant geneticist is investigating the inheritance of genes for bitter taste (Su) and explosive rind (e) in watermelon (Cit

mylen [45]

Answer:

See the answer below

Explanation:

Using the formula for calculating Chi square ( $X^2$ ):

$X^2$ = $\frac{(O - E)^2}{E}$ where O = observed frequency and E = expected frequency.

The observed frequencies for the four phenotypes are 88, 62, 62, and 81 respectively.

For the expected frequency, the phenotypes are supposed to assort in 9:3:3:1 according to Mendel ratio.

Hence, expected frequencies are calculated as:

phenotype (1) = 9/16 x 293 = 164.81

phenotype (2) = 3/16 x 293 = 54.94

phenotype (3) = 3/16 x 293 = 54.94

phenotype (4) = 1/16 x 293 = 18.31

The $X^2$ is calculated thus:

Phenotype O E $X^2$

1 88 164.81 $\frac{(88 - 164.81)^2}{164.81}$ = 35.80

2 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

3 62 54.94 $\frac{(62 - 54.94)^2}{54.94}$ = 0.91

4 81 18.31 $\frac{(81 - 18.31)^2}{18.31}$ = 214.64

Total $X^2$ = 35.80 + 0.91 + 0.91 + 214.64 = 252.26

To the nearest tenth = 252

Degree of freedom = n - 1 = 4- 1 = 3

$X^2$ tabulated = 7.815

The calculated  $X^2$  exceeds the critical value, hence, the null hypothesis is rejected. The two genes did not assort independently. 

4 0

2 years ago

The statement "the variety and number of

enyata [817]

Answer:

Biodiversity

Explanation:

refers to all the variety of life that can be found on Earth (plants, animals, fungi and micro-organisms) as well as to the communities that they form and the habitats in which they live.

7 0

3 years ago

What substance would need to be added in order to reverse the reaction?

Korvikt [17]

The substance that would be added in order to reverse the reaction would be any substance that is found in the product side. Adding a substance that tends to be a product will shift the equilibrium of the system and will allow the reaction to produce the substances that is found in the reactant side.

5 0

2 years ago

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