Cells of same type group together to form tissue.
<span>The correct answer is B, I just took the test.
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Answer:
B
Explanation:
We never see short bristle males, suggesting some type of lethality. I.e. any males who inherit the mutation die before birth so we don't see the phenotype. This also hints that it could be X-linked.
Females can be short bristled, but males can't, as it is likely lethal. This suggests that having one copy of the short bristle trait without the long bristle trait is lethal (as males as XY and so only have one copy of the trait). The female then must be heterozygous for the short bristle trait (which also explains how in generation F2, long bristle males can be produced, as if she was homozygous males would all be short bristled, and therefore dead, so there would be no males.
Since the first short bristle female is heterozygous, the trait for short bristles must be dominant.
However, since evidence suggests the trait is X-linked, it cannot be autosomal, as suggested in B.
