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4 years ago

Please help with this square problem, the picture is shown.

Mathematics

1 answer:

Galina-37 [17]4 years ago

5 0

Area of the upper rectangle = x(16 - 6) = 10x yd²

Area of the bottom rectangle = 6(x + 6) = 6x + 36 yd²

Total area = 10x + 6x + 36 = 16x + 36 yd²

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This function can be used to determine the number of bacteria in a culture h hours after the culture was started.

dimulka [17.4K]

Answer:

The statement means that after 2 hours, there are 90 bacteria in the culture.

Step-by-step explanation:

The number of bacteria after x hours is given by the function states in the exercise. We have that f(x) will be the number of bacteria after x hours.

Which statement best describes the meaning of the equation f(2) = 90 ?

The statement means that after 2 hours, there are 90 bacteria in the culture.

3 0

3 years ago

4. On the day Alex was born, his father invested $5000 in an account with a 1.2% annual growth rate.

mihalych1998 [28]

Answer and Step-by-step explanation:

A) A(t) = 5000(1 + 0.012)t

B) A(t) = 106260

A) 5000 is the initial amount, 1 + 0.012 is the interest rate, and t represents the years.

B) When we plug 21 into the equation, we get 106260.

I hope this helps!

7 0

4 years ago

The height (feet) of an object moving vertically is given by s= (-16t^2)+(208t)+(156), where t is in seconds.

OverLord2011 [107]

Answer:

The object's velocity at t = 7 is -16 ft/s

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

Step-by-step explanation:

From the information given, the equation of motion of the object is

$s(t)= -16t^2+208t+156$

For any equation of motion s(t), the instantaneous velocity at time t is given by

$v(t)=\frac{ds}{dt}$

(a) To find the object's velocity at t = 7, you must:

$v(t)=\frac{d}{dt}(-16t^2+208t+156)\\\\v(t)=-\frac{d}{dt}\left(16t^2\right)+\frac{d}{dt}\left(208t\right)+\frac{d}{dt}\left(156\right)\\\\v(t)=-32t+208+0\\\\v(t)=-32t+208$

Next, we evaluate when t = 7

$v(7)=-32(7)+208=-224+208\\\\v(7)=-16$

The object's velocity at t = 7 is -16 ft/s

(b) To find the maximum of a function we always use the derivative of the function and we set it equal zero to find the critical points.

To find the maximum height and when it occurs, we set the velocity function equal to 0 and solve for t.

$-32t+208=0\\\\-32t+208-208=0-208\\\\-32t=-208\\\\\frac{-32t}{-32}=\frac{-208}{-32}\\\\t=\frac{13}{2}$

Next, we substitute this value into the equation of motion to find the maximum height

$s(\frac{13}{2})= -16(\frac{13}{2})^2+208(\frac{13}{2})+156\\\\s(\frac{13}{2})=-676+1352+156)=832$

The maximum height is 832 ft and it occurs when $t=\frac{13}{2}$

6 0

3 years ago

F(x)=x2+8x+6. What is the value of f(4)?

dezoksy [38]

46

When it says f(4) that means x=4

So you then just fill in all the x’s with 4’s and solve as normal

4 0

3 years ago

Divide 571.85 by 1,500. Round to the nearest thousandth

arsen [322]

The answer would be 0.381.

8 0

4 years ago

Read 2 more answers