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Molodets [167]
4 years ago
12

Special right triangles Help me find s

Mathematics
1 answer:
dalvyx [7]4 years ago
5 0

Answer:

s = 3\sqrt{3}

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos30° = \frac{\sqrt{3} }{2}

cos30° = \frac{adjacent}{hypotenuse} = \frac{s}{6} = \frac{\sqrt{3} }{2} ( cross- multiply )

2s = 6\sqrt{3} ( divide both sides by 2 )

s = 3\sqrt{3}

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