Question

Special right triangles Help me find s

Answer 1

Answer:

s = 3$\sqrt{3}$

Step-by-step explanation:

Using the cosine ratio in the right triangle and the exact value

cos30° = $\frac{\sqrt{3} }{2}$

cos30° = $\frac{adjacent}{hypotenuse}$ = $\frac{s}{6}$ = $\frac{\sqrt{3} }{2}$ ( cross- multiply )

2s = 6$\sqrt{3}$ ( divide both sides by 2 )

s = 3$\sqrt{3}$