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trapecia [35]
3 years ago
11

Evaluate math pls help algebra

Mathematics
2 answers:
Ne4ueva [31]3 years ago
4 0

Answer:

a. is equal to -10

b. is equal to -1

c. is equal to 5

Step-by-step explanation:

a :

3(-2)-4

-6-4

-10

b :

3(1)-4

3-4

-1

c :

3(3)-4

9-4

5

These are the correct answers,please mark brainliest.

Free_Kalibri [48]3 years ago
3 0

Answer:

A. -10

B. -1

C. 5

Step-by-step explanation:

A. 3x-4 = 3(-2)-4 = -10

B. 3x-4 = 3(1)-4 = -1

C. 3x-4 = 3(3)-4 = 5

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Stoplight a changes color every 30 seconds and stoplight b changes every 40 seconds. after how many seconds will the stoplights
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Answer:

After 120 seconds

Step-by-step explanation:

Here, we want to know the number of seconds after which both spotlights will change colors at the same time again.

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Resolve into partial fractions<br><br>​
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Answer:

See below

Step-by-step explanation:

1)

\frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A}{2 - x}  +  \frac{B}{x - 3}  \\  \\  \therefore \:  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{A(x - 3) +B(2 - x) }{(2 - x)(x - 3)}   \\  \\ \therefore \:  11 + x = Ax - 3A + 2B - Bx \\  \\  \therefore \: 11 + x = - 3A  + 2B  + Ax -  Bx\\  \\  \therefore \: 11 + x = - 3A  + 2B  + (A - B)x \\  \\ equating \: the \: like \: terms \: on \: both \: sides \\ A - B = 1 \\  \therefore \: A  =  B  +  1.....(1) \\  \\  -  3A  + 2B = 11....(2) \\  from \: eq \: (1) \: and \: (2) \\  - 3(B  +  1) + + 2B = 11 \\  \\ - 3B   - 3  + 2B = 11 \\  \\  - B = 11 + 3 \\  \\ B =  - 14  \\ A  =   - 14 +  1 =  - 13 \\  \\  \frac{11 + x}{(2 - x)(x - 3)}  =  \frac{ - 13}{2 - x}  +  \frac{ - 14}{x - 3} \\  \\ \frac{11 + x}{(2 - x)(x - 3)}  = -   \frac{ 13}{2 - x}   -  \frac{ 14}{x - 3}

2)

\frac{12x + 11}{x^2 +x - 6}

=\frac{12x + 11}{x^2 +3x-2x - 6}

=\frac{12x + 11}{x(x +3) -2(x +3)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{12x + 11}{(x +3) (x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A}{(x +3)}+\frac{B}{(x - 2)}

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{A(x-2)+B(x+3)}{(x-2)(x+3)}

\therefore 12x + 11 = A(x-2)+B(x+3)

\therefore 12x + 11 = Ax-2A+Bx+3B

\therefore 12x + 11 = Ax+Bx-2A+3B

\therefore 12x + 11 = (A+B) x-2A+3B

Equating like terms on both sides:

A + B = 12\implies A = 12-B... (1)

- 2A + 3B = 11... (2)

Solving equations (1) & (2), we find:

A = 5, B = 7

\therefore \frac{12x + 11}{x^2 +x - 6}=\frac{5}{(x +3)}+\frac{7}{(x - 2)}

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