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3 years ago

What kind of chemical reaction does the chemical equation sodium + chlorine sodium chloride represents

Physics

1 answer:

Pavlova-9 [17]3 years ago

5 0

It represents combustion.

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What obstacles or challenges are encountered in magnetic levitation?

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3 years ago

A simple pendulum is made from a 0.75-m-long string and a small ball attached to its free end. The ball is pulled to one side th

Alecsey [184]

Answer:

It takes 0.43 seconds before the pendulum attains the maxium speed.

Explanation:

L= 0.75m

g= 9.8 m/s²

T= 2π * √(L/g)

T=1.73 sec

T(vmax) = T/4

T(vmax) = 0.43 sec

8 0

4 years ago

A stone is thrown horizontally at a speed of 10.0 m/s from the top of a cliff 139.4 m high.

Lesechka [4]

Answer:

a) 14.2sec

b) 1394m away if horizontal speed never changes

c) 9.8m/s

Explanation:

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3 years ago

Find the values of the root mean square translational speed v, molecules in gaseous diatomic oxygen (O2), gaseous carbon dioxide

tiny-mole [99]

Answer:

For diatomic oxygen:V=539.06 m/s

For carbon dia oxide:V=459.71 m/s

For dia atomic hydrogen:V=2156.25 m/s

Explanation:

As we know that

Root mean square velocity V

$V=\sqrt{\dfrac{3RT}{M}}$

Where

R is the gas constant

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

T is the temperature (K).

M is the molecular weight.

For diatomic oxygen:

M=32 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{32\times 10^{-3}}}$

V=539.06 m/s

For carbon dia oxide

M=44 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{44\times 10^{-3}}}$

V=459.71 m/s

For dia atomic hydrogen:

M= 2 g/mol

T=273+100 = 373 K

$R=8.31\ \frac{kg.m^2}{s^2.mol.K}$

$V=\sqrt{\dfrac{3RT}{M}}$

$V=\sqrt{\dfrac{3\times 8.31\times 373}{2\times 10^{-3}}}$

V=2156.25 m/s

3 0

4 years ago

A block of mass 3.7 kg, which has an initial velocity of 7.9 m/s at time t = 0, slides on a horizontal surface. Calculate the wo

Lady_Fox [76]

Answer:

115.6 J

Explanation:

$m$ = mass of the block = 3.7 kg

$v_{f}$ = final speed of the block = 0 ms⁻¹

$v_{o}$ = initial speed of the block = 7.9 ms⁻¹

$W$ = work done on the block

Using work done - change in kinetic energy theorem, we have

$W = (0.5) m (v_{o}^{2} - v_{f}^{2})\\W = (0.5) (3.7) (7.9^{2} - 0^{2})\\W = 115.6 J$

5 0

4 years ago

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