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kap26 [50]
3 years ago
15

wypiszcie motywy baśniowe( postaci i wydarzenia); motywy legendarne ( postaci i wydarzenia); postaci i wydarzenia realistyczne b

alladyna 7 klasa
Physics
1 answer:
djverab [1.8K]3 years ago
8 0

axghisxbiwzi exbifavizaibibxwbbiaxvidaxwbixabizbabjaxibwbiaxn,noazbaxoboxsbixihdahglhkWibbizwzigvzbBvBzju

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when the particles of the medium move back and forth along the direction of the wave motion, the wave is a
Bezzdna [24]

Transverse waves are always characterized by particle motion being perpendicular to wave motion. A longitudinal wave is a wave in which particles of the medium move in a direction parallel to the direction that the wave moves.

8 0
3 years ago
Read 2 more answers
A rectangular tank is filled to a depth of 10m with freshwater and open to air at atmospheric pressure.
charle [14.2K]

Answer:

<em>1.</em> <em>39068.07 N</em>

<em>2. 19534.036 N</em>

Explanation:

depth of water h = 10 m

atmospheric pressure Patm = 101325 Pa

density of water p = 1000 kg/m^3

acceleration due to gravity g = 9.81 m/s^2

pressure due to depth of water = pgh

P = 1000 x 9.81 x 10 = 98100 Pa

total pressure on the bottom of the tank is Patm + p = 101325 + 98100 = 199425 Pa

Left plug has diameter = 50 cm = 0.5 m

radius = 0.5/2 = 0.25 m

height = 1 cm = 0.01 m

<em>height below tank surface = 10 - 0.01 = 9.99</em>

pressure at this depth =  1000 x 9.81 x 9.99 = 98001.9 Pa

<em>total pressure = Patm + P = 101325 + 98001.9 = 199326.9 Pa</em>

surface area of plug = πr^{2} = 3.142 x 0.25^{2} = 0.196 m^{2}

<em>force required to lift left plug = pressure x area</em>

F =  199326.9 x 0.196 = <em>39068.07 N</em>

<em>The right side is a hemisphere with the same diameter, therefore surface area is half of the left plug</em>

A = 0.196/2 = 0.098 m^{2}

force F required to lift right plug =  199326.9  x 0.098 =<em> 19534.036 N</em>

6 0
3 years ago
true or false? destructive interference occurs when a trough meets up with another trough given location along the medium
disa [49]

Answer:Poopy-di scoop

Scoop-diddy-whoop

Whoop-di-scoop-di-poop

Poop-di-scoopty

Scoopty-whoop

Whoopity-scoop, whoop-poop

Poop-diddy, whoop-scoop

Poop, poop

Scoop-diddy-whoop

Whoop-diddy-scoop

Whoop-diddy-scoop, poop

Explanation:

4 0
3 years ago
a 1500 kg car traveling at 15 m/s to the south collides with a 4500 kg truck that is intially at rest at a spotlight. The car an
harkovskaia [24]

Answer:

3.75 m/s south

Explanation:

Momentum before collision = momentum after collision

m₁ u₁ + m₂ u₂ = m₁ v₁ + m₂ v₂

Since the car and truck stick together, v₁ = v₂.

m₁ u₁ + m₂ u₂ = (m₁ + m₂) v

Given m₁ = 1500 kg, u₁ = -15 m/s, m₂ = 4500 kg, and u₂ = 0 m/s:

(1500 kg) (-15 m/s) + (4500 kg) (0 m/s) = (1500 kg + 4500 kg) v

-22500 kg m/s = 6000 kg v

v = -3.75 m/s

The final velocity is 3.75 m/s to the south.

4 0
3 years ago
Read 2 more answers
An object, with a final position of x = 100.1 meters, initially started at x = -12.13 meters. What was its displacement? (Unit =
nikklg [1K]

Answer:

112.23 m

Explanation:

Displacement is the final position minus the initial position.

Δx = x − x₀

Δx = 100.1 m − (-12.13 m)

Δx = 112.23 m

8 0
3 years ago
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