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pishuonlain [190]
2 years ago
10

Richard is driving home to visit his parents. 135 mi of the trip are on the interstate highway where the speed limit is 65 mph .

Normally Richard drives at the speed limit, but today he is running late and decides to take his chances by driving at 73 mph .
Physics
1 answer:
Elis [28]2 years ago
5 0
<h2>Answer:</h2>

He saves 13.2 minutes

<h2>Explanation:</h2>

Hey! The question is incomplete, but it can be found on the internet. The question is:

How many minutes did he save?

Let's call:

t_{1}:Time \ at \ speed \ 65mph \\ \\ t_{2}:Time \ at \ speed \ 73mph \\ \\ v_{1}=65mph \\ \\ v_{2}=73mph

We know that the 135 miles are on the interstate highway where the speed limit is 65 mph. From this, we can calculate the time it takes to drive on this highway. Assuming Richard maintains constant the speed:

v=\frac{d}{t} \\ \\ d:distance \\ \\ t:time \\ \\ v:velocity \\ \\ t_{1}=\frac{d}{v_{1}} \\ \\ t=\frac{135}{65} \\ \\ t_{1}=2.07 \ hours

Today he is running late and decides to take his chances by driving at 73 mph, so the new time it takes to take the trip is:

t_{2}=\frac{135}{73} \\ \\ t_{2}=1.85 \ hours

So he saves the time t_{s}:

t_{s}=t_{1}-t_{2}=2.07-1.85=0.22 \ hours

In minutes:

t_{s}=0.22h\left(\frac{60min}{1h}\right) \\ \\ \boxed{t_{s}=13.2min}

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Minimum diameter is required for the wire is 1.2X10⁻³m.

Tensile force, which consists of tensile stress and tensile strain, is the stretching force exerted on the material. This indicates that the forces are attempting to stretch the material that is subject to the force since it is under tension.

Given;

Tensile force (ft) = 780 N

length (l) = 3.00 mm

change in length (Δl) = 0.25 cm

determine the strain ε = Δl/l

determine the stress σ = Eε = E(Δl/l)

determine the cross-sectional area A = f/σ = ft/EΔl

determine the diameter d = 2\sqrt{} \frac{A}{\pi } = 2\sqrt{} \frac{ft}{EXΔlX\pi }

take Young's modulus for steel E=200 GPa, Substitute the values,

d = \sqrt[2]{\frac{x780X2}{y200X10^{9} X 0.0025\pi } } = 1.2X10⁻³

minimum diameter is required for the wire is 1.2X10⁻³m.

Learn more about the Tensile force with the help of the given link:

brainly.com/question/4443489

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I understand that the question you are looking for is "A circular steel wire 3.00 cm long must stretch no more than 0.25 cm when a tensile force of 780 N is applied to each end of the wire. What minimum diameter is required for the wire?"

4 0
1 year ago
A ship travels 84 km on a bearing of 17°, and then travels on a bearing of 107° for 135 km. Find the distance of the end of the
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Answer:

159km

Explanation:

Please view the diagram below;

The distance x of the ship from the staring point could be simply obtained by Pythagoras's theorem as follows;

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50mph,60mph

Explanation:

Let speed of southbound train=x mph

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Distance between two trains after 1.5 hour,174 miles.

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Using the formula

174=1.5x+1.5(x+16)

174=1.5(x+x+16)

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2 years ago
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