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Fittoniya [83]
4 years ago
6

A watermelon is dropped from the top of a 80m tall building. We want to find the velocity of the watermelon after it falls for 1

.35s. We can ignore air resistance.
Kinematics formula would be most helpful to solve for the target unknown?

Answer choices in picture.

Physics
1 answer:
White raven [17]4 years ago
7 0

Answer:

v_f = v_i + at

v_f = 13.23 m/s

Explanation:

Height Of the watermelon when it is dropped is given as

h = 80 m

time of fall under gravity

t = 1.35 s

now if water melon start from rest then we have

v_i = 0

acceleration due to gravity for watermelon

a = 9.81 m/s^2

now we need to find the final speed of watermelon

v_f = v_i + at

so we will have

v_f = 0 + (9.81)(1.35)

v_f = 13.23 m/s

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\sf \qquad \qquad \huge \underbrace{єхplαnαtiσn}

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