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Yuki888 [10]
3 years ago
14

Select the interval where f(x)>0 A: -2 B: 1< x<2 C: 4 HELP

Mathematics
1 answer:
Viefleur [7K]3 years ago
7 0

Answer: 1 < x < 2

Step-by-step explanation:

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igor_vitrenko [27]

Answer:

3^(n+1) - 3^n / 3^(n-1)​ = 6

7 0
3 years ago
you are working to save money for a trip you need to save at least 1000 dollars if you already have 350 saved and you make $8 an
4vir4ik [10]
$1000 dollars is how much you need to pay for the trip.
You already have $350.
$1000 - $350 = $650.  So, you need to make $650 more.
$650 <span>÷ 8 = 81.25

So you final answer is:  81.25 hours.

Hope this helped you!  :D





</span>
8 0
3 years ago
Does anyone have access to Big Ideas Learning Algebra 1 Assessment book? I would greatly appreciate it if you could place the li
laiz [17]
Can't you just make a new user
8 0
3 years ago
PLEASE HELP!!!!!!!!!!!!!!
Alex17521 [72]

Answer:

angle = 50.8° (to the nearest tenth of a degree)

Step-by-step explanation:

In a right triangle:

  • The angle between the shorter leg and the hypotenuse is the larger acute angle of the triangle.
  • The angle between the longer leg and the hypotenuse is the smaller acute angle of the triangle.

We have been given the measures of the <u>shorter leg</u> and the <u>hypotenuse</u>, so the angle between them is the <u>larger acute angle</u> (which we need to find).

shorter leg = 3√6 cm

hypotenuse = 3√15 cm

So to find the angle, we need to use the trig ratio: cos(\theta)=\frac{adjacent}{hypotenuse}

If \theta is the angle, then the short leg is the "adjacent" side to the angle and the "hypotenuse" is the hypotenuse.

Substituting the given values:

cos(\theta)=\frac{3\sqrt{6} }{3\sqrt{15} }

⇒ \theta=arccos(\frac{3\sqrt{6} }{3\sqrt{15} })=50.76847952..

Therefore, the angle = 50.8° (to the nearest tenth of a degree)

3 0
3 years ago
Help! How do I do this?
Leni [432]

Step-by-step explanation:

remember, the sum of all angles in a triangle is always 180°.

and the sum of all angles around one point at one side of a line is also airways 180° (because you can imagine that point to be the center of a circle, and the line would cut that circle in half = 180° for every half).

in the triangle LKM we know 2 angles already :

angle 1 = 44°

angle K = 90° (right angle).

so, angle 2 = 180 - 90 - 44 = 46°

and so, angle 5 = 180 - 46 = 134°.

as the angles around point L on line KL are the angles 2 and 5.

angle 5 = 134°

4 0
2 years ago
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