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PolarNik [594]
4 years ago
10

At a certain point between Earth and the Moon, the net gravitational force exerted on an object by Earth and the Moon is zero. T

he Earth-Moon centre-to-centre seperation is 3.84 x 10^5 km. The mass of the Moon is 1.2% the mass of Earth . . a) where is this point located? Are there any other such points? . . b) What is the physical meaning of the root of the quadratic equation whose value exceeds the Earth-Moon distance?
Physics
1 answer:
FinnZ [79.3K]4 years ago
3 0
The related equation is 
F = G mE mM/d^2
Given the distance between the two:
F = G mE mM/(384000-d^2)

mM is 1.2 of mE and applying law of proportionality:

mE/d^2 = 0.012 mE/(384000-d^2)

Solving for d using the calculator, the answer is 
d1 =5.88x10^5 km and d2 =2.86 x10^5 km. 
The net gravitation is the distance where d2 =2.86 x10^5 km. There is no physical meaning when <span>d1 =5.88x10^5 km </span>
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Answer:

The correct answer is:

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Explanation:

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Answer:

v = 72.54 m/s

Explanation:

We have,

Length of a guitar string is 0.62 m

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The velocity of the wave in the string is given by :

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