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PolarNik [594]
4 years ago
10

At a certain point between Earth and the Moon, the net gravitational force exerted on an object by Earth and the Moon is zero. T

he Earth-Moon centre-to-centre seperation is 3.84 x 10^5 km. The mass of the Moon is 1.2% the mass of Earth . . a) where is this point located? Are there any other such points? . . b) What is the physical meaning of the root of the quadratic equation whose value exceeds the Earth-Moon distance?
Physics
1 answer:
FinnZ [79.3K]4 years ago
3 0
The related equation is 
F = G mE mM/d^2
Given the distance between the two:
F = G mE mM/(384000-d^2)

mM is 1.2 of mE and applying law of proportionality:

mE/d^2 = 0.012 mE/(384000-d^2)

Solving for d using the calculator, the answer is 
d1 =5.88x10^5 km and d2 =2.86 x10^5 km. 
The net gravitation is the distance where d2 =2.86 x10^5 km. There is no physical meaning when <span>d1 =5.88x10^5 km </span>
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A circular wire loop of radius LaTeX: RR lies in the xy-plane with the z-axis running through its center. There is initially no
frosja888 [35]

Answer:

Explanation:

Given a circular loop of radius R

r = R

Note: the radius lies in the xy plane

Area is given as

A = πr² = πR²

At t = 0, no magnetic field B=0

The magnetic field is given as a function of time

B = C•exp(t) •i + D•t² •k

Where C and D are constant

We want to find the magnitude of EMF in the circular loop.

EMF is given as

ε = - N•dΦ/dt

Where,

N is number of turn and in this case we will assume N = 1.

Φ is magnetic flux and it is given as

Φ = BA

ε = - N•d(BA)/dt

Where A is a constant, then we have

ε = - N•A•dB/dt

B = C•exp(t) •i + D•t² •k

dB/dt = C•exp(t) •i + 2D•t •k

Then,

ε = - N•A•dB/dt

ε = - 1•πR²•(C•exp(t) •i + 2D•t •k)

ε = -πR²•(C•exp(t) •i + 2D•t •k)

So, let find the magnitude of EMF

Generally finding magnitude of two vectors R = a•i + b•j

Then, |R| = √a² + b²

So, applying this we have,

ε = πR² (√(C²•exp(2t) + 4D²t²))

From the given magnetic field, we are given that,

B = 0 at t = 0

B = C•exp(t) •i + D•t² •k

B = 0 = C•exp(0) •i + D•0² •k

0 = C

Then, C = 0.

So, substituting this into the EMF.

ε = πR² (√(0²•exp(2t) + 4D²t²))

ε = πR² (√4D²t²)

ε = πR² × 2Dt

ε = 2πDR²t

So, the EMF is also a function of time

ε = 2πDR²t

4 0
4 years ago
A child in danger of drowning in a river is being carried down-stream by a current that flows uniformly with a speed of 2.20 m/s
zmey [24]

Answer:

The angle is 65.6°.

Explanation:

Given that,

Speed = 2.20 m/s

Distance from the shore= 500 m

Distance from the bottom= 1100 m

Speed of boat = 7.30 m/s

According to figure,

We need to calculate the angle with shore

Using formula of angle

\tan\theta=\dfrac{y}{x}

Put the value into the formula

\tan\theta=\dfrac{500}{1100}

\theta=\tan^{-1}(\dfrac{500}{1100})

\theta=24.4^{\circ}

We need to calculate the angle

\alpha=90-\theta

Put the value into the formula

\alpha=90-24.4

\alpha=65.6^{\circ}

Hence, The angle is 65.6°.

5 0
3 years ago
An object is located 50 cm from a converging lens having a focal length of 15 cm. Which of the following is true regarding the i
Diano4ka-milaya [45]

Answer:

It is real, inverted, and smaller than the object.

Explanation:

First of all, we can use the lens equation to find the location of the image:

\frac{1}{q}=\frac{1}{f}-\frac{1}{p}

where

q is the distance of the image from the lens

f = 15 cm is the focal length (positive for a converging lens)

p = 50 cm is the distance of the object from the lens

Solving the equation for q,

\frac{1}{q}=\frac{1}{15 cm}-\frac{1}{50 cm}=0.047 cm^{-1}\\q=\frac{1}{0.047 cm^{-1}}=21.3 cm

The distance of the image from the lens is positive, so we can already conclude that the image is real.

Now we can also write the magnification equation:

{h_i}=-h_o \frac{q}{p}

where h_i, h_o are the size of the image and of the object, respectively.

Substituting p = 50 cm and q = 21.3 cm, we have

{h_i}=-h_o \frac{21.3 cm}{50 cm}=-0.43 h_o

So from this relationship we observe that:

|h_i| < |h_o| --> this means that the image is smaller than the object, and

h_i < 0 --> this means that the image is inverted

so, the correct answer is

It is real, inverted, and smaller than the object.

4 0
3 years ago
We often use a spoon to cool coffee by stirring. Some of the heat is conducted from the coffee to the air by this method, but th
Ilia_Sergeevich [38]

Answer:

Explanation:

heat lost by coffee = heat gain by aluminum spoon

heat lost by coffee = mc ( 85° C - T)

175 ml of water = 175 grams

175 grams = (175 / 1000) kg = 0.175 kg

heat loss by coffee = 0.175 × 4182 J/Kgk ( 85 - T) = 731.85 ( 85-T) = 62207.25 - 731.85 T

heat gain by aluminum spoon = 0.012kg × 897 J/kgK ( T - 22) = 10.764 T - 236.808

10.764 T - 236.808 = 62207.25 - 731.85 T

10.764 T + 731.85 T = 62207.25 + 236.808

T = 84.086 ° C approx 84°C

3 0
3 years ago
Define the term scientific theory and scientific law
AnnyKZ [126]

Answer:

https://www.livescience.com/21457-what-is-a-law-in-science-definition-of-scientific-law.html

To Read more

Explanation:

A scientific law is the description of an observed phenomenon. It doesn't explain why the phenomenon exists or what causes it. The explanation of a phenomenon is called a scientific theory. It is a misconception that theories turn into laws with enough research.

Please Mark as Brainliest

6 0
3 years ago
Read 2 more answers
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