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2 years ago

If a boy weighs 490 N and stands on a flat rough surface with a

Physics

1 answer:

OleMash [197]2 years ago

8 0

The force of static friction acting on the boy is 333 Newtons.

Hence, option (d) 333N is the correct answer.

Given the data in the question;

Weight of boy; $F_n = 490N$

Coefficient of static friction; $u_s = 0.68$

Force of static friction acting on the boy; $F_s = \ ?$

<h3>Friction</h3>

Friction is simply referred as the resistance an object experience when moving or trying to move over another object. It can either by dynamic or static.

Static friction is the resistance experienced by a body at rest.

Coefficient of friction is the measure of how easily a body moves in relation to the other.

Static friction is expressed as;

$F_s = u_s * F_n$

Where $F_s$ is the normal force and $u_s$ is the coefficient of static friction.

We substitute our given values into the equation above

$F_s = u_s * F_n\\\\F_s = 0.68 * 490N\\\\F_s = 333.2N\\\\F_s = 333N$

The force of static friction acting on the boy is 333 Newtons.

Hence, option (d) 333N is the correct answer.

Learn more friction: brainly.com/question/17237604

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