If a boy weighs 490 N and stands on a flat rough surface with a
1 answer:
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Given the data in the question;
- Weight of boy;
- Coefficient of static friction;
Force of static friction acting on the boy;
Friction is simply referred as the resistance an object experience when moving or trying to move over another object. It can either by dynamic or static.
Static friction is the resistance experienced by a body at rest.
Coefficient of friction is the measure of how easily a body moves in relation to the other.
Static friction is expressed as;
Where is the normal force and
is the coefficient of static friction.
We substitute our given values into the equation above
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Learn more friction: brainly.com/question/17237604
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Answer:
a)
Explanation:
- Since the car speeds up at a constant rate, we can use the kinematic equation for distance (assuming that the initial position is x=0, and choosing t₀ =0), as follows:
- Since the car starts from rest, v₀ =0.
- We know the value of t = 5 sec., but we need to find the value of a.
- Applying the definition of acceleration, as the rate of change of velocity with respect to time, and remembering that v₀ = 0 and t₀ =0, we can solve for a, as follows:
- Replacing a and t in (1):
- Now, if the truck slows down at a constant rate also, we can use (1) again, noting that v₀ is not equal to zero anymore.
- Since we have the values of vf (it's zero because the truck stops), v₀, and t, we can find the new value of a, as follows:
- Replacing v₀, at and t in (1), we have:
- Therefore, as the truck travels twice as far as the car, the right answer is a).