Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres
If a boy weighs 490 N and stands on a flat rough surface with a
1 answer:
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Given the data in the question;
- Weight of boy;
- Coefficient of static friction;
Force of static friction acting on the boy;
Friction is simply referred as the resistance an object experience when moving or trying to move over another object. It can either by dynamic or static.
Static friction is the resistance experienced by a body at rest.
Coefficient of friction is the measure of how easily a body moves in relation to the other.
Static friction is expressed as;
Where is the normal force and
is the coefficient of static friction.
We substitute our given values into the equation above
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Learn more friction: brainly.com/question/17237604
You might be interested in
Maximum height
= (Usinα)^2/2g
(50*0.5)^2/20
25^2/20
625/20
=31.25metres
horizontal distance = Range= [U^2 * sin2α]/g
[50^2 * sin60]/10
2500 * 0.8660/10
2165/10=216.5metres
Answer:
Explanation:
If we have a periodic wave we need to satisfy the following basic relationship:
From the last formula we see that the velocity is proportional fo the frequency.
For this case we have the following info given by the problem:
We know that the frequency is the reciprocal of the period so we have this formula:
And if we replace we got:
Now since we have the value for the wavelength we can find the velocity like this:
And if we convert this into cm/s we got: