If a boy weighs 490 N and stands on a flat rough surface with a
1 answer:
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Given the data in the question;
- Weight of boy;
- Coefficient of static friction;
Force of static friction acting on the boy;
Friction is simply referred as the resistance an object experience when moving or trying to move over another object. It can either by dynamic or static.
Static friction is the resistance experienced by a body at rest.
Coefficient of friction is the measure of how easily a body moves in relation to the other.
Static friction is expressed as;
Where is the normal force and
is the coefficient of static friction.
We substitute our given values into the equation above
The force of static friction acting on the boy is 333 Newtons.
Hence, option (d) 333N is the correct answer.
Learn more friction: brainly.com/question/17237604
You might be interested in
Answer:
The rate of flow of water is 71.28 kg/s
Solution:
As per the question:
Diameter, d = 18.0 cm
Diameter, d' = 9.0 cm
Pressure in larger pipe, P =
Pressure in the smaller pipe, P' =
Now,
To calculate the rate of flow of water:
We know that:
Av = A'v'
where
A = Cross sectional area of larger pipe
A' = Cross sectional area of larger pipe
v = velocity of water in larger pipe
v' = velocity of water in larger pipe
Thus
v' = 4v
Now,
By using Bernoulli's eqn:
where
h = h'
Now, the rate of flow is given by: