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Goryan [66]
3 years ago
11

How do you think a graph of deceleration would differ from a graph showing acceleration

Physics
2 answers:
zloy xaker [14]3 years ago
6 0
A graph of acceleration would have to be a graph with an increasing slope, since you're going faster and faster

a graph of deceleration would have to be a graph with a negative slope since you are slowing down over time
Levart [38]3 years ago
6 0
Simply, a deceleration starts from top and goes down, and acceleration goes from bottom to top.
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A race car drives one lap around a race track that is 500 meters in length.
pychu [463]

Explanation:

Check out the picture I drew for a minute before reading this...

B. Distance [the red line] is a scalar quantity reflecting how far an object has traveled. Displacement [the green line] is a vector quantity reflecting how far an object has moved from a point. The key difference is that distance can be any sort of path while displacement is always a vector (or a straight line) between a starting point and a finishing point. Sometimes distance and displacement are equal to one another. Sometimes you have a distance traveled, but zero displacement overall; which is what's going on in your question.

A. The distance that the racecar traveled is indeed 500m. But at the end of the lap, it is right back where it started. So overall, it has been displaced 0m.

3 0
2 years ago
How can i tell the difference between a one element and another?
dybincka [34]


Normally, the number of electrons is equal to the number of protons, which makes atoms electrically neutral. The number of protons in an atom is the defining feature of an atom. It's what makes one element different from another

HOPE THIS HELPS!!!

8 0
3 years ago
Read 2 more answers
A 12.0 cm object is 9.0 cm from a convex mirror that has a focal length of -4.5 cm. What is the distance of the image from the m
Rasek [7]

Answer:

- 3 cm

Explanation:

From the mirror formula;

1/f = 1/v + 1/u ; where f is the focal length, v is the image distance, and u is the object distance.

1/-4.5 = 1/9 + 1/v

1/v = -1/4.5 - 1/9

    = -1/3

Therefore;

v = -3 cm

Hence;

Image distance is - 3cm

5 0
2 years ago
What percent of air by volume is nitrogen​
nlexa [21]

Answer:

78 percent

Explanation:

I guess that's the right answer

5 0
3 years ago
How man significant figures does the following value gave 43.023
Varvara68 [4.7K]

Answer:

It has 5 I hope this helps you

7 0
2 years ago
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