How do you think a graph of deceleration would differ from a graph showing acceleration
2 answers:
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Answer:
The minimum frequency required to ionize the photon is 111.31 × Hertz
Given:
Energy = 378
To find:
Minimum frequency of light required to ionize magnesium = ?
Formula used:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
Solution:
The energy of photon of light is given by,
E = h v
Where E = Energy of magnesium
h = planks constant
v = minimum frequency of photon
738 × = 6.63 ×
× v
v = 111.31 × Hertz
The minimum frequency required to ionize the photon is 111.31 × Hertz
Answer:
The tunnel probability for 0.5 nm and 1.00 nm are and
respectively.
Explanation:
Given that,
Energy E = 2 eV
Barrier V₀= 5.0 eV
Width = 1.00 nm
We need to calculate the value of
Using formula of
Put the value into the formula
(a). We need to calculate the tunnel probability for width 0.5 nm
Using formula of tunnel barrier
Put the value into the formula
(b). We need to calculate the tunnel probability for width 1.00 nm
Hence, The tunnel probability for 0.5 nm and 1.00 nm are and
respectively.