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klemol [59]
3 years ago
13

21 out of 70 of the athletes wore green shorts. Which fraction is equivalent to this?

Mathematics
2 answers:
Soloha48 [4]3 years ago
8 0

Answer:

Step-by-step explanation: 21/70

Ymorist [56]3 years ago
3 0

Answer: the answer is

42/140

or

3/10

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Which pair(s) of expression are equal in value? Check all that apply
ankoles [38]

Note: Since the symbols for greatest integer function (GIF) and least integer function (LIF) are not given, I will be using the words GIF and LIF in the solution

GIF x means largest integer less than or equal to x, and LIF x means least integer greater than or equal to x.

We need to determine which expressions are equal

Option 1: GIF 4.9 and LIF 3.1

GIF 4.9 =  3

LIF 3.1 = 4

Hence GIF 4.9 ≠ LIF 3.1

Option 2: GIF 15.2 and GIF 14.8

GIF 15.2 = 15

GIF 14.8 = 14

Hence, GIF 15.2 ≠ GIF 14.8

Option 3: GIF -6 and LIF -6

GIF -6 = -6

LIF -6 = -6

Hence, GIF -6 = LIF -6

Option 4: LIF -3.2 and LIF -2.6

LIF -3.2 = -2

LIF -2.6 = -1

Hence, LIF -3.2 ≠ LIF -2.6

Hence, only in Option C the pair of expressions are equal.

3 0
4 years ago
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Hiiiii! ok plz plz help!!!! i’ll mark brainlist first answer! also know that ur worth every breath! <3
murzikaleks [220]

Answer: True

Step-by-step explanation:

Cost = 15 + 3t

22.5 = 15 + 3(2.5)

22.5 = 15 + 7.5

22.5 = 22.5 <— true

8 0
3 years ago
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The circumference of Circle F is 72 cm. What is the length of Arc DE (the minor arc)?
Tom [10]

You need to first set up the equation:

It would look like 90 divided by 360 multiplied by the given circumference which is 72 cm.

So 90 / 360 x 72

Simply the fraction above, it will give us:

¼ x 72

So the answer would be 18 cm that is the length of DE (minor arc)

4 0
4 years ago
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Can someone pls pls pls help me Evaluate the expression 6.908 – g for g = 0.173.
Serjik [45]

Answer:

6.735

Step-by-step explanation:

im smart

4 0
3 years ago
Help me plss, number 2.​
Gnesinka [82]

Answer:

At (-2,0) gradient is -4 ; At (2,0) gradient is 4

Step-by-step explanation:

For this problem, we simply need to take the derivative of the function and evaluate when y = 0 (when crossing the x-axis).

y = x^2 - 4

y' = 2x

The function y = x^2 - 4 cross the x-axis when:

y = x^2 - 4

0 = x^2 - 4

4 = x^2

2 +/- = x

Hence, this curve crosses the x-axis twice, once at (-2,0) and again at (2,0).

The gradient at these points are as follows:

y' = 2(-2) = -4

y' = 2(2) = 4

Cheers.

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4 years ago
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