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2 years ago

A right rectangular prism has these dimensions:

Mathematics

1 answer:

Andreyy892 years ago

7 0

I believe the volume would be 0.74^3

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big water canoeing company rents conoes for 75$ per hour. explain why the point (0,0) and (1, 75) are on the graph of the relati

Pepsi [2]

The X (1) axis represents the number of hours, and the Y (75) axis represents the number of dollars. When 0 hours are passed, 0 hours are payed (0,0) 1 hour 75 dollars are payed (1, 75) 2 hours 150 dollars is payed (2, 150) and so on

3 0

2 years ago

Rearrange the equation A = xy to solve for x.

mote1985 [20]

X = A/y
You divide the y from both sides
The y on the right cancels
On the left you have A/y = x

5 0

2 years ago

Some friends made a salad for a party. there were 28 people at the party including the friends. they bought enough cherry tomato

zubka84 [21]

Just do 28 times 3 and you will get 84 to check this just divide 84 to 28.....

8 0

2 years ago

Suppose the probabilities for the letters on a spinner are known to be: p(A)=1/4 p(B)=1/3 p(C)=5/12 predict the number of times

svlad2 [7]

Answer:

You will end up on A 3 times, B 4 times, and C 5 times.

Step-by-step explanation:

Just divide 12 by each value and you get your answer.

7 0

1 year ago

Assume a standard deviation of LaTeX: \sigma = 0.75σ = 0.75. You plan to take a random sample of 110 households, what is the pro

olchik [2.2K]

Answer:

P(2.50 < Xbar < 2.66) = 0.046

Step-by-step explanation:

We are given that Population Mean, $\mu$ = 2.58 and Standard deviation, $\sigma$ = 0.75

Also, a random sample (n) of 110 households is taken.

Let Xbar = sample mean household size

The z score probability distribution for sample mean is give by;

Z = $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

So, probability that the sample mean household size is between 2.50 and 2.66 people = P(2.50 < Xbar < 2.66)

P(2.50 < Xbar < 2.66) = P(Xbar < 2.66) - P(Xbar $\leq$ 2.50)

P(Xbar < 2.66) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ < $\frac{2.66-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z < -1.68) = 1 - P(Z $\leq$ 1.68)

= 1 - 0.95352 = 0.04648

P(Xbar $\leq$ 2.50) = P( $\frac{Xbar-\mu}{\frac{\sigma}{\sqrt{n} } }$ $\leq$ $\frac{2.50-2.78}{\frac{0.75}{\sqrt{110} } }$ ) = P(Z $\leq$ -3.92) = 1 - P(Z < 3.92)

= 1 - 0.99996 = 0.00004

Therefore, P(2.50 < Xbar < 2.66) = 0.04648 - 0.00004 = 0.046

3 0

2 years ago