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Kisachek [45]
3 years ago
6

Find the difference between theproduct of 26.22 and 3.09 and the sum of 3.507, 2.08, 11.5, and 16.712. 

Mathematics
2 answers:
Firlakuza [10]3 years ago
7 0
The difference between the product of 26.22 and 3.09 and sum of 3.507, 2.08, 11.5 and 16.712

Now this looks messy, change them into numerals:
(26.22 × 3.09) - (3.507 + 2.08 + 11.5 + 16.712)
Clear the parenthesis:
81.0198 - 33.799
Subtract:
47.2208

Answer is: A. 47.2208
ioda3 years ago
6 0
<span> 26.22× 3.09  </span>≈  <span>81.0198– 3.507  </span>≈ <span>7 7.5128– 2.08  </span>≈ <span> 75.4328– 11.5  </span>≈  <span>63.9328– 16.712
</span>≈47.2208 Your answer is A
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Step-by-step explanation:

Given that:

the sample proportion p = 0.39

sample size = 100

Then np = 39

Using normal approximation

The sampling distribution from the sample proportion is approximately normal.

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(b)

Here;

the sample proportion = 0.39

the sample size n = 400

Since np = 400 * 0.39 = 156

Thus, using normal approximation.

From the sample proportion, the sampling distribution is approximate to the mean \mu_{\hat p} =  p = 0.39

the standard deviation \sigma_{\hat p} = \sqrt{\dfrac{p(1-p)}{n} }

\sigma_{\hat p} = \sqrt{\dfrac{0.39 (1-0.39)}{400} }

\sigma_{\hat p} =0.0244

The test statistics can be computed as:

Z = \dfrac{{\hat _{p}} - \mu_{_ {\hat p}} }{\sigma_{\hat p}}

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P (\hat p \le 0.3 ) = P(z \le -3.69)

\mathbf{P (\hat p \le 0.3 ) = 0.0001}

(c) The effect of the sample size on the sampling distribution is that:

As sample size builds up, the standard deviation of the sampling distribution decreases.

In addition to that, reduction in the standard deviation resulted in increases in the Z score, and the probability of having a sample proportion  that is less than 30% also decreases.

6 0
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Answer:

I think it's 12

Step-by-step explanation:

Hope it helps!

5 0
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