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zhuklara [117]
4 years ago
12

There are ten bird baths in a park. On the first day of​ spring, the bird baths are filled. Several weeks​ later, the overall ch

ange in the water level is found. The results are shown in the table. What is the range of the​ data?
2.5
0.7
-2.2
2.1
2.3
-1.6
1.1
-2.4
2.7
1.2
Mathematics
1 answer:
daser333 [38]4 years ago
3 0

Answer:

4.5

Step-by-step explanation:

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A line is perpendicular to y=2/3x +2/3 and intersects the point (-2,4). what is the equation of this perpendicular line?
TiliK225 [7]

hope it helps..................

5 0
2 years ago
∠C and ​ ∠D ​ are vertical angles with m∠C=−x+26 and m∠D=2x−10 . What is m∠D ? Enter your answer in the box.
Musya8 [376]
-x+26=2x-10
+x +10  +x +10
36+3x
divde by 3
12=x

m∠D=2(12)-10
        =24-10
        =14
8 0
4 years ago
Read 2 more answers
I need help with box and whisker plots ASAP
bonufazy [111]
Box and whiskers plots use five number summaries. The first number is:
1:Minimum
2.Quartile 1
3.Mean
4.Quartile 2
5.maximum

Quartile are simple to get.
If your set of numbers is:
2,3,3,6,8,8,11
Then find the mean
2 3 3 |6| 8 8 11
Find the mean of the left side of of mean.
2 |3| 3 3 =Quartile 1
Then the right side
8 |8| 11 8 =Quartile 2
-----------------------------------------------
Your 5 number summary is 2,3,6,8,11
Plot them on the number line, but put a line above where the dot would go. take the 3 middle lines and connect to make a box. The lines on the outside of the box are the whiskers, AKA distributed data.
8 0
3 years ago
Consider the system of equations. 20 POINTS NEED HELP ASAP
Alex

- 5x - 1 = 2x + 6

- 7x = 7

7x = -7

x = -1

3 0
2 years ago
An open rectangular box with square base has a volume of 256 cubic inches. determine the equation for the volume and surface are
Serjik [45]
Let
b-----------> the length side of the square box
h------------> the height of the box
SA---------> surface area of the box

we know that
[volume of the box]=b²*h
volume=256 in³
b²*h=256-------> h=256/b²-----> equation 1

surface area of the box=area of the base+perimeter of base*height

area of the base=b²
perimeter of the base=4*b

surface area=b²+(4*b)*h------> SA=b²+4*b*h-----> equation 2

substitute equation 1 in equation 2
SA=b²+4*b*[256/b²]-----> SA=b²+1024/b-----> SA=(b³+1024)/b

the answer is

the formula of the volume of the box is  V=b²*h-----> 256=b²*h

the formula of the surface area of the box are
SA=b²+4*b*h
SA=(b³+1024)/b
4 0
3 years ago
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