Answer:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
Step-by-step explanation:
b. 
a. ![\displaystyle [8x + 12y]^2 + [6x + 9y]^2 = [10x + 15y]^2](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5B8x%20%2B%2012y%5D%5E2%20%2B%20%5B6x%20%2B%209y%5D%5E2%20%3D%20%5B10x%20%2B%2015y%5D%5E2)
The two expressions are identical on each side of the equivalence symbol, therefore they are an identity.
I am joyous to assist you anytime.
Answer:
In quadrilateral ABCD we have
AC = AD
and AB being the bisector of ∠A.
Now, in ΔABC and ΔABD,
AC = AD
[Given]
AB = AB
[Common]
∠CAB = ∠DAB [∴ AB bisects ∠CAD]
∴ Using SAS criteria, we have
ΔABC ≌ ΔABD.
∴ Corresponding parts of congruent triangles (c.p.c.t) are equal.
∴ BC = BD.
Answer:
58
Step-by-step explanation:
Just trust me on this. It has got to be 58.
Answer:
6r+7=13+7r
6r+7=7r+13
6r+7−7r=7r+13−7r
−r+7=13
−r+7−7=13−7
−r=6
= 
r=−6
Step-by-step explanation:
:) This is the answer
Answer:
Step-by-step explanation:
∠CAB = 33 {alternate interior angles}
5x = 33 + 2x { exterior angle equals sum of opposite interior angles}
5x - 2x = 33
3x = 33
x = 33/3
x = 11
∠B = 2x = 2* 11 = 22
∠ECB = 5x = 5*11 = 55