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aksik [14]
3 years ago
12

At a busy intersection, a 1320-kg car traveling west with a speed of 12 m/s collides head-on with a minivan traveling east with

a speed of 9.4 m/s. The cars stick together and move with a velocity of 1.5 m/s to the east after the collision. What is the mass of the minivan
Physics
1 answer:
Elza [17]3 years ago
7 0
p = mv so this question pertains to conservation of momentum.

The momentum of the car is 1320*12 = 15840kgms^-1
For the sake of easiness and the fact negatives are annoying, I will assume east to be positive.

So we know 9.4m - 15840 = (1320+m)*1.5
9.4m - 15840 = 1980+1.5m

Rearranging to solve for m
7.9m = 17820
m = 2255.70 = 2300kg to 2sf

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When a car of mass 1167 kg accelerates from 10.0 m/s to some final speed, 4.00  10 5J of work are done. Find this final speed.
Akimi4 [234]
  • Mass=1167kg
  • Initial velocity=u=10m/s
  • Acceleration=a=4m/s^2
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  • Final velocity=v=?
  • Force=F
  • Distance=d

Apply Newton's second law

\\ \tt\hookrightarrow F=ma

\\ \tt\hookrightarrow F=1167(4)=4668N

Now

\\ \tt\hookrightarrow W=Fd

\\ \tt\hookrightarrow d=\dfrac{W}{F}

\\ \tt\hookrightarrow d=\dfrac{105}{4668}

\\ \tt\hookrightarrow d=0.022m

Now

  • d be s

According to third equation of kinematics

\\ \tt\hookrightarrow v^2=u^2+2as

\\ \tt\hookrightarrow v^2=10^2+2(4)(0.022)

\\ \tt\hookrightarrow v^2=100+8(0.022)

\\ \tt\hookrightarrow v^2=100+0.176

\\ \tt\hookrightarrow v^2=100.176

\\ \tt\hookrightarrow v=10.001m/s

8 0
2 years ago
Another machine uses an input of 200 newtons to produce an output force of 80 newtons what is the mechanical advantage of this m
Rina8888 [55]

If the input machine produces an output of 80 Newtons, then the mechanical advantage is that it produces work. If the required output must be 80 Newtons, then the input force is desirable having 100 percent production of force even though it requires a large amount of input to produce 80 Newtons of force.

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Acceleration involves a change in speed and _______<br> (Fill in the blank space)
ASHA 777 [7]
Acceleration involves a change in speed and Direction
5 0
3 years ago
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When an aluminum bar is connected between a hot reservoir at 860 K and a cold reservoir at 348 K, 2.40 kJ of energy is transferr
Natalija [7]

Answer:

a) \Delta S_{in} = 2.791\,\frac{J}{K}, b) \Delta S_{out} = 6.897\,\frac{J}{K}, c) S_{gen} = 4.106\,\frac{J}{K}, d) Due to irreversibilities due to temperature differences.

Explanation:

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\Delta S_{in} = \frac{2400\,J}{860\,K}

\Delta S_{in} = 2.791\,\frac{J}{K}

b) The change in entropy of the cold reservoir is:

\Delta S_{out} = \frac{2400\,J}{348\,K}

\Delta S_{out} = 6.897\,\frac{J}{K}

c) The total change in entropy of the Universe is modelled after the Second Law of Thermodynamics. Let assume that process is steady:

\Delta S_{in} - \Delta S_{out} + S_{gen} = 0

S_{gen} = \Delta S_{out} - \Delta S_{in}

S_{gen} = 6.897\,\frac{J}{K} - 2.791\,\frac{J}{K}

S_{gen} = 4.106\,\frac{J}{K}

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Answer:

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Explanation:

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