Answer : The value of the constant for a second order reaction is, 
Explanation :
The expression used for second order kinetics is:
![kt=\frac{1}{[A_t]}-\frac{1}{[A_o]}](https://tex.z-dn.net/?f=kt%3D%5Cfrac%7B1%7D%7B%5BA_t%5D%7D-%5Cfrac%7B1%7D%7B%5BA_o%5D%7D)
where,
k = rate constant = ?
t = time = 17s
= final concentration = 0.0981 M
= initial concentration = 0.657 M
Now put all the given values in the above expression, we get:


Therefore, the value of the constant for a second order reaction is, 
Answer:
I) You walk barefoot on the hot street and it burns your toes.
II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.
Explanation:
In conduction mode of heat transfer we know that the energy is transferred from one system to other system due to direct contact of two bodies
Here due to this direct contact the energy is transferred via a given solid or liquid medium
In this type of heat transfer medium particles will remain in its own position only the energy is transferred.
So here we can say the correct answer will be
I) You walk barefoot on the hot street and it burns your toes.
II) When you get into a car with hot black leather in the middle of the summer and your skin starts to get burned.
Here's the tool you need. You can't answer the question without this:
"1 watt"
means
"1 joule of energy, generated, used, or moved, every second".
So 60 watts = 60 joules per second
Total energy generated,
used, or moved = (power) x (time).
580 joules = (60 watts) x (time)
Divide each side
by (60 watts): Time = (580 joules) / (60 joules/sec)
= (9 and 2/3) seconds .
Physical, chemical, chemical, physical, I’m pretty sure. Natural things, like you starting to breathe heavier are physical most of the time!!!
Answer:
Normal force = 8.75 N
Explanation:
given,
frictional force between the steel spatula and the Teflon frying pan=0.350 N
coefficient of friction between material =0.04
normal force = ?
using formula,
Frictional force = coefficient of friction × normal force


Normal force = 8.75 N