The answer is B, when you subtract 400N from 600N, you are left with 200N in net force.
Answer:
0.34s, 8.5m,31.89m
Explanation:
The above motion defines a projectile motion.
Now the athletes lands on a cliff 30° to the horizontal this means the velocity at that point would be 25m/s cos30°
Now from Newton's law of motion.
The body would be decelerating so,
V = u - gt
Where u is initial velocity and v is final velocity. g is acceleration of free fall due to gravity.
Hence,
V-U/ -g = t
Hence 25cos30 - 25/ -9.8 = 0.34s.
2.Now the length of the jump is defined as the total horizontal distance which is marked off by the horizontal velocity and time taken for take off and landing.
Hence Distance,S = u × t
25 ×0.34 =8.5m.
3. The maximum height is defined that at that point the Final velocity is 0m/s
Now the initial velocity is 25m/s
From Newton's law that;
V2= U2 -2gH; where U and V are initial and final velocity and H is height.
Hence H = V2-U2/-2g
=(0)^2- (25)^2/ -2×9.8
= -625/-19.6 =31.89m
Answer:
Explanation:
Given
mass
Force
coefficient of static friction
coefficient of static friction
maximum Static Friction will be given by
initially we need to provide a force of 1040 N to move the Pig . As soon Pig starts moving kinetic friction will come into play.
But maximum force is less than Maximum static friction force so it is impossible to move pig.
Answer:This is the part of the scientific method that tests your hypothesis. An experiment is a tool that you design to find out if your ideas about your topic are right or wrong.
Explanation:
Answer:
1.87 ms-2
Explanation:
We need to convert the velocity from km/hr to m/s as follows;
100 × 1000/3600 = 27.7 m/s
Also
120 × 1000/3600 = 33.3 m/s
From;
v= u + at
v= 33.3 m/s
u= 27.7 m/s
t= 3 secs
v= u + at
a = v- u/t
a = 33.3 - 27.7/3
a= 1.87 ms-2