El factor mas importante para el exceso de peso es un exceso de energía creada por una alimentación excesiva
El peso de un cuerpo es definido por la relación entre la energía requerida para los procesos vitales del cuerpo, sus actividades físicas diarias y la energía suministra en forma de alimentos.
Cuando estos dos parámetros están en balance el peso es estable, pero cuando la cantidad de alimentos aumenta o el valor energético de los mismo aumenta se tiene un exceso de energía que el cuerpo almacena en forma de grasa corporal, este el el factor mas importante para el exceso de peso.
En conclusión el factor mas importante para el exceso de peso es un exceso de energía por una alimentación excesiva
aprende mas acerca del peso corporal aquí:
brainly.com/question/13032223
Answer:
A lone neutron spontaneously decays into a proton plus an electron.
Explanation:
In an atom, nuclei contain protons and neutrons, which are the fundamental particles of an atom. Neutrons are stable and uncharged particles inside a nucleus.
For 15 times during its lifetime, a free neutron decays and breaks down into more smaller particles.This breakdown causes problems in nuclear reactors, as they start decaying and emit radiations of different wavelengths.
A neutron undergoes the decaying process to produce an electron, a proton, and energy.
The reaction of neutron decay:
n0 → p+ + e− + νe
Answer:
K.E=365.2 J
Explanation:
Given data
Weight w =953 N
radius r=1.68 m
F=73.9 N
t=2.55 s
g=9.8 m/s²
To find
Kinetic Energy K.E
Solution
From the moment of inertia
The angular acceleration is given as
The angular velocity is given as
So the Kinetic Energy is given as
Answer:
Distance covered is equal to all the distance traveled.
So for example, if you go from A to B, and then from B to C, the total distance covered is AB + BC.
Displacement is equal to the difference between the final position and the initial position.
So if we go from A to B, the displacement is simply the line AB.
While if we go from A to B, and then from B to C, the displacement will be a segment that directly connects A and C, such that:
displacement = √( (AB)^2 + (BC)^2)
Now, if we want to find the points such that the magnitude of the distance covered is equal to the magnitude of the displacement, we need to look at the pairs that are directly connected by a straight line.
Those are:
A to B ( or B to A)
B to C (or C to B)
C to D (or D to C)
