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Sedaia [141]
3 years ago
13

NEED ANSWER IMMEDIANTELY What is the net force on this object? A) 0N it is balanced B) 200N down C) 400N up D) 600N down

Physics
2 answers:
yaroslaw [1]3 years ago
4 0
The answer is B, when you subtract 400N from 600N, you are left with 200N in net force.
Ulleksa [173]3 years ago
4 0

The Answer would be answer B.200Ndown

Hope this helps

Please mark as Brainliest(;

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A mass is attached to a spring with an unknown spring constant. The spring gains 10 J of elastic potential energy if stretched b
Firlakuza [10]

From the given information in the question, the correct option is Option 1: 14 cm.

A non-stretched elastic spring has a conserved potential energy which gives it the ability to perform work. The elastic potential energy can be expressed as:

PE = \frac{1}{2} k x^{2}

Where PE is the energy, k is the spring constant and x is extension.

i. Given that: PE = 10 J and x = 10 cm, then;

PE = \frac{1}{2} k x^{2}

10 = \frac{1}{2} k 10^{2}

20 = 100k

k = 0.2 J/cm

ii. To determine how far the spring is needed to be stretched, given that PE = 20 J.

PE = \frac{1}{2} k x^{2}

20 = \frac{1}{2} (0.2) x^{2}

40 = 0.2 x^{2}

x^{2} = 200

x = \sqrt{200}

  = 14.1421

x = 14.14 cm

So that;

x is approximately 14.00 cm.

Thus, the spring need to be stretched to 14.00 cm to give the spring 20 J of elastic potential energy.

For more information, check at: brainly.com/question/1352053.

8 0
3 years ago
From your ____ chest to your___ shoulders you must have been wearing
natita [175]
Sorry I don’t know the exact answer
7 0
2 years ago
A shopper pushes a 5.32 kg grocery cart
Juli2301 [7.4K]

Answer:

\text { acceleration of the cart is } 10.94 \mathrm{m} / \mathrm{s}^{2}

Explanation:

According to “Newton's second law”

“Force” is “mass” times “acceleration”, or F = m× a. This means an object with a larger mass needs a stronger force to be moved along at the same acceleration as an object with a small mass

Force = mass × acceleration

\text { Acceleration }=\frac{\text { force }}{\text { mass }}

Given that,

Mass = 5.32 kg

\text { Force }=12.7 \mathrm{N} \text { forces at }-28.7^{\circ}

x=-28.7^{\circ}

F = 12.7N

Normal force = mg + F sinx,  

“m” being the object's "mass",  

“g” being the "acceleration of gravity",

“x” being the "angle of the cart"

\mathrm{g}=9.8 \mathrm{m} / \mathrm{s}^{2}\text { (g is referred to as the acceleration of gravity. Its value is } 9.8 \mathrm{m} / \mathrm{s}^ 2 \text { on Earth })

To find normal force substitute the values in the formula,

Normal force = 5.32 × 9.8 + 12.7 × sin(-28.7)

Normal force = 52.136 + 12.7 × 0.480

Normal force = 52.136 + 6.096

Normal force = 58.232 N

<u>Acceleration of the cart</u>:

\text { Acceleration }=\frac{\text {Normal force}}{\text { mass }}

\text { Acceleration }=\frac{58.232}{5.32}

\text { Acceleration }=10.94 \mathrm{m} / \mathrm{s}^{2}

\text { Therefore, "acceleration of the cart" is } 10.94 \mathrm{m} / \mathrm{s}^{2}

7 0
2 years ago
Read 2 more answers
in an automobile crash, a vehicle that was stopped at a red light is rear-ended by another vehicle. The vehicles have the same m
baherus [9]

The initial speed of the vehicle before the collision is 8 m/s.

  • Let the mass of the vehicle = m
  • Let the initial speed of the vehicle stopped = u
  • The initial speed of the vehicle parked at the red light = 0

<h3>Principle of conservation of linear momentum</h3>
  • The initial speed of the vehicle before the collision is calculated by applying principle of conservation of linear momentum as follows;

m_1 u_1 + m_2 u_2 = v(m_1 + m_2)\\\\mu + m(0) = 4(m+ m)\\\\mu = 4(2m)\\\\mu = 8m\\\\u = 8 \ m/s

Thus, the initial speed of the vehicle before the collision is 8 m/s.

Learn more about inelastic collision here: brainly.com/question/7694106

6 0
2 years ago
Approximate the human form as an unclothed vertical cylinder of 0.3 m diameter and 1.75 m length with a surface temperature of 3
Zolol [24]

Answer:

q=1118.865W

Explanation:

From the question we are told that

Diameter of the cylinder D=0.3m

Length of the cylinder L=1.75m

Surface temperature of cylinder T_s=30 \textdegree C=303k

Speed of air V=10m/s

Temperature of air T=20 \textdegree C

Generally the equation for Reynolds number is mathematically given by

Re_D=\frac{VD}{v}

where

v=15.27*10^-^6

Re_D=\frac{10*0.3}{15.27*10^-^6}

Re_D=1.96*10^5

Generally the equation for Nusselt number is mathematically given by

N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}

where

Prandtl number

Pr=0.71

N_u=0.6(Re_D)^{0.6}(Pr)^{0.37}

N_u=0.6(1.96*10^5)^{0.6}(0.71)^{0.37}

N_u=791.53

Generally the equation for convective heat transfer is mathematically given by

h=Nu \frac{k}{D}

where

k=25.7*10^{-3}

h=791.53*\frac{25.7*10^{-3}}{0.3}

h=67.81W/m^2K

Generally the equation for surface area of a cylinder is mathematically given by

A=\pi DL

A=\pi *0.3*1.75

A=1.65m^2

Generally the equation for convective heat transfer is mathematically given by

q=h4(T_s-T_{inty)}

q=(67.81)*1.65*(30-20)\\

q=1118.865W

3 0
2 years ago
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