In which situation is the gravitational force between two objects hard to detect?

Physics

2 answers:

Bond [772]2 years ago

4 0

Answer&Explanation:

According to the Newton gravitational law is directly proportional to the Product between masses and inversely proportional to the square of the distance..

Hence from the law and corresponding question the correct answer is D:if the mass of each object is very small

Thus it would make it undetectable

iren2701 [21]2 years ago

3 0

Answer:

Explanation:

Newton's Law of Gravitation states that:

$F_G = \frac{-Gm_1m_2}{r^2}$

If the masses of each object is small, then $m_1*m_2$ would be very small, making the gravitational force between the two objects hard to detect - as it itself would be very small.

You might be interested in

A man pushed a cabinet with a force of 200N. What is the mass of the cabinet that accelerates 4 m/s/s?

ELEN [110]

Answer:

$\boxed {\boxed {\sf 50 \ kg}}$

Explanation:

We are asked to find the mass of a cabinet, given the force and acceleration. According to Newton's Second Law of Motion, force is the product of mass and acceleration. The formula for this is:

$F= m \times a$

The force is 200 Newtons, but we should convert the units to make unit cancellation easier. 1 Newton is equal to 1 kilogram meter per second squared, so the force of 200 Newtons is 200 kilogram meters per second squared.

The mass is unknown and the acceleration is 4 meters per second per second or 4 meters per second squared.

F= 200 kg*m/s²
a= 4 m/s²

Substitute the values into the formula.

$200 \ kg *m/s^2 = m \times 4 \ m/s^2$

We are solving for the mass, m, so we must isolate the variable. It is being multiplied by 4 meters per second squared. The inverse operation of multiplication is division. Divide both sides by 4 m/s²

$\frac {200 \ kg *m/s^2}{4 \ m/s^2}= \frac{m \times 4\ m/s^2}{4 \ m/s^2}$