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3 years ago

In which situation is the gravitational force between two objects hard to detect?

Physics

2 answers:

Bond [772]3 years ago

4 0

Answer&Explanation:

According to the Newton gravitational law is directly proportional to the Product between masses and inversely proportional to the square of the distance..

Hence from the law and corresponding question the correct answer is D:if the mass of each object is very small

Thus it would make it undetectable

iren2701 [21]3 years ago

3 0

Answer:

Explanation:

Newton's Law of Gravitation states that:

$F_G = \frac{-Gm_1m_2}{r^2}$

If the masses of each object is small, then $m_1*m_2$ would be very small, making the gravitational force between the two objects hard to detect - as it itself would be very small.

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To view an interactive solution to a problem that is similar to this one, select Interactive Solution 7.24. A 0.0146-kg bullet i

Vinil7 [7]

Answer:

0.25223 seconds.

Explanation:

$m_1$ = Mass of bullet = 0.0146 kg

$m_2$ = Mass of block = 2.55 kg

v = Combined velocity

$u_1$ = Velocity of bullet = 816 m/s

g = Acceleration due to gravity = 9.81 m/s²

As linear momentum is conserved

$m_1u_1 + m_2u_2 =(m_1 + m_2)v$

Now $u_2=v$ as the block (with the bullet in it) reverses direction and rises,

$m_1u_1 + m_2v =(m_1 + m_2)v\\\Rightarrow m_1u_1=(m_1 + m_2)v-m_2v\\\Rightarrow 0.0146\times 816=(0.0146 + 2.55)v-(-2.55v)\\\Rightarrow 11.9136=2.2646v+2.55v\\\Rightarrow 11.9136=4.8146v\\\Rightarrow v=\frac{11.9136}{4.8146}\\\Rightarrow v=2.47447\ m/s$

Equation of motion

$v=u+at\\\Rightarrow t=\frac{v-u}{a}\\\Rightarrow t=\frac{2.47447-0}{9.81}\\\Rightarrow t=0.25223\ s$

The time t is 0.25223 seconds.

3 0

3 years ago

What is a good way to study guys for a science test Im in need because I have a quiz tmrw

nikklg [1K]

Answer:

Space out your studying. Nate Kornell “definitely did cram” before big tests when he was a student. ...

Practice, practice, practice! ...

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Test yourself. ...

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Explanation:

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2 years ago

A ball accelerates from rest down a ramp at 2.4 m/s^2. Write an equation that could be used to determine the balls finals positi

Alik [6]

Answer:

x=2.4t+4.9t^2

Explanation:

This equation is one of the kinematic equations to solve for distance. The original equation is as follows:

X=Xo+Vt+1/2at^2

We know that the ball starts at rest meaning that its initial velocity and position is zero.

X=0+Vt+1/2at^2

Since it is going down the ramp, you can use the acceleration of gravity constant. (9.81 m/s^2) and simplify that with the 1/2.

X=Vt+4.9t^2

Note: Since the positive direction in this problem is down, you are adding the 4.9t^2, but if a question says that the downward direction is negative, you would subtract those values.

Now, substitute in your velocity value.

X=2.4t+4.9t^2

8 0

2 years ago

What is the difference between static and Kenetic friction?

rusak2 [61]

Static friction is the friction between an object at rest and the surface on which it is resting on.

Kinetic friction is the friction between a moving object and the surface on which it moves.

Hopefully you understood and this helps :)

3 0

4 years ago

What would be the change in pressure if height of liquid column above the

Setler79 [48]

Answer:

The height of the liquid column doesn't affect the pressure on top pressure ina liquid is affected by the weight of the above it

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3 years ago