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Vesna [10]
3 years ago
10

8 colors according to their alphabetical order​

Physics
1 answer:
damaskus [11]3 years ago
6 0

Answer:

8 colors in alphabetical order are

Black

blue

brown

Green

Orange

Pink

Purple

Yellow

Explanation:

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What is the measurement 111.009 mm rounded off to four significant digits?
dedylja [7]
111.0 because 111.009 rounds off to 111.01, thus rounding again off to 111.0
4 0
3 years ago
Given that the frequency of an EM wave is 4THz, what is its wavelength?
Vilka [71]

Answer:

The wavelength of the EM wave is 7.5 * 10⁻⁴ m

Explanation:

The velocity of a wave is related to its wavelength by the following formula;

velocity = wavelength * frequency

For an electromagnetic (EM) wave, its velocity is equal to the velocity of light, c = 3.0 * 10⁸ m/s

Given that the frequency and veloity of the given EM wave in the question is known, its wavelength is calculated as follows:

wavelength = velocity/frequency

where velocity of the EM wave = 3.0 * 10⁸ m/s;

frequency = 4THz = 4 * 10¹² Hz

wavelength = 3.0 * 10⁸m/s / 4 * 10¹² Hz

wavelength = 7.5 * 10⁻⁴ m

Therefore, the wavelength of the EM wave is 7.5 * 10⁻⁴ m

8 0
3 years ago
A boxcar at a rail yard is set into motion at the top of a hump. The car rolls down quietly and without friction onto a straight
enyata [817]

Answer:

I have answer with explanations in each of the six (6) special cases.

Explanation:

Please find attached the detailed solution to all your questions.

3 0
3 years ago
With what speed would mail pass through the center of the Moon if falling in a tunnel that runs through the center
ratelena [41]

Answer:

$v_f = = 7.9 \times10^3 \text{ m/s }$

7 0
3 years ago
Assume that the force of a bow on an arrow behaves like the spring force. In aiming the arrow, an archer pulls the drawstring ba
Alex

Answer:

 v=39.05 m/s

Explanation:

Given that

x= 56 cm

F= 158 N

m= 58 g = 0.058 kg

Lets take spring constant = k

At the initial position,before releasing the arrow

F= k x

By putting the values

F= k x

158= 0.56 k

k=282.14 N/m

Now from energy conservation

Lets take final speed of the arrow after releasing

\dfrac{1}{2}kx^2=\dfrac{1}{2}mv^2

k x²=mv²

282.14 x 0.56² = 0.058 v²

v=39.05 m/s

3 0
3 years ago
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