<span> Na2CO3 + 2HCl = CO2 + H2O + 2NaCl
this is the double displacement reaction
</span><span>2 Na(+) + CO3(-2) + 2H(+) + 2Cl(-) ------> 2Na(+) + 2 Cl(-) + H2O + CO2
</span>2Na+ and 2Cl- are the spectator ions as they appear on the both sides of equation :
so the net ionic equation can be written as :
CO3(-2) + 2H(+) -------------> <span>H2O + CO2</span>
Answer:
The amount left after 49.2 years is 3mg.
Explanation:
Given data:
Half life of tritium = 12.3 years
Total mass pf tritium = 48.0 mg
Mass remain after 49.2 years = ?
Solution:
First of all we will calculate the number of half lives.
Number of half lives = T elapsed/ half life
Number of half lives = 49.2 years /12.3 years
Number of half lives = 4
Now we will calculate the amount left after 49.2 years.
At time zero 48.0 mg
At first half life = 48.0mg/2 = 24 mg
At second half life = 24mg/2 = 12 mg
At 3rd half life = 12 mg/2 = 6 mg
At 4th half life = 6mg/2 = 3mg
The amount left after 49.2 years is 3mg.
Moles of P = 56,4g/30,974g/mole = 1,82 moles P
moles of O = 43,6/15,999 = 2,73 moles of O
converting to the simplest ratio:
For P : 1,82/1,82 = 1
For O : 2,73/1,82 = 1,5
1 P and 2 oxygens.
PO2 -> the empirical formula
hope this help
Yes. Strong bases are too. In fact, they’re more dangerous to your skin than acids.
There’s no graph soooooooio
