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Novay_Z [31]
3 years ago
6

Is the following shape a rectangle? How do you know?

Mathematics
2 answers:
trasher [3.6K]3 years ago
7 0

Answer: The answer is (D). No, the adjacent sides are not perpendicular.

Step-by-step explanation: We are given a shape on the co-ordinate plane and we are to check the correct statement about the shape from the given options.

The shape has four vertices A(4, -1), B(2, 4), C(-2, 2) and D(0, -3). So, the shape is definitely a quadrilateral. We are to check whether it is a rectangle or not.

We will find the slope of all the sides AB(m), BC(n), CD(o) and DA(p) as follows:

m=\dfrac{4+1}{2-4}=-\dfrac{5}{2},\\\\n=\dfrac{2-4}{-2-2}=\dfrac{1}{2},\\\\o=\dfrac{-3-2}{0+2}=-\dfrac{5}{2},\\\\p=\dfrac{-3+1}{0-4}=\dfrac{1}{2}.

Since,

m=o,~~n=p,

so the opposite sides are parallel, but

m\times n\neq -1,~~n\times o\neq -1,~~o\times p\neq -1,~~p\times m\neq -1,

so the adjacent sides are not perpendicular.

Thus, (D) is the correct option.

xenn [34]3 years ago
3 0

The answer is C. No, the adjacent sides are not perpendicular. (Apex)

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What is the solution of -8 / 2 y - 8 equals 5 / y + 4 - 7 y + 8 / Y 2 - 16​
AysviL [449]

Answer:

The value of y is 6.

Step-by-step explanation:

The given equation is

\dfrac{-8}{2y-8}=\dfrac{5}{y+4}-\dfrac{7y+8}{y^2-16}

It can be rewritten as

\dfrac{-8}{2(y-4)}=\dfrac{5}{y+4}+\dfrac{7y+8}{y^2-4^2}

\dfrac{-4}{(y-4)}=\dfrac{5}{y+4}+\dfrac{7y+8}{(y+4)(y-4)}

Multiply both sides by (y+4)(y-4).

(y+4)(y-4)(\dfrac{-4}{(y-4)})=(y+4)(y-4)(\dfrac{5}{y+4})+(y+4)(y-4)(\dfrac{7y+8}{(y+4)(y-4)})

(y+4)(-4)=(y-4)(5)+7y+8

-4y-16=5y-20-(7y+8)

-4y-16=5y-20-7y-8

-4y-16=-2y-28

-4y+2y=-28+16

-2y=-12

Divide both sides by -2.

y=6

Therefore, the value of y is 6.

5 0
3 years ago
What is the interval notation for the compound inequality? x ≤ −4 or x ≥ 5
torisob [31]

Answer:

(-∞, -4] ∪ [5, ∞)

Step-by-step explanation:

Hi!

Alright, so greater (or less) than or equal to is denoted with a bracket.

If x is less than or equal to -4, then the bracket is on the left side.

(___, -4]

Because x is <em>any</em> number under or equal to -4, x can range from negative infinity. However, we use a parentheses for infinity because infinity can never truly be reached.

So, x \leq -4 = (-∞, -4]

X\geq5

Equal to = bracket

X is any number above 5, so

[5, ∞)

Because we want both of these, we use the union sign (∪)

so,

= (-∞, -4] ∪ [5, ∞)

8 0
3 years ago
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