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babymother [125]
3 years ago
11

Write an expression for " the quotient of q and 9​

Mathematics
1 answer:
Dmitry_Shevchenko [17]3 years ago
8 0

Answer:

q/9

Step-by-step explanation:

The quotient is an number or variable that is the product of division. My answer may be reversed or wrong, but it should be close to the correct one.

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- 3 ( n + 5 ) = 12<br> What is N?
lana66690 [7]
The answer will be n=-9

5 0
2 years ago
Given that parallelogram ABCD and angle D=145 what is the measure of angle C
stiv31 [10]
Opposite angles of parallelogram are equal.
sum of interior angles of parallelogram is 360 degrees.

Therefore,
A + B + C + D = 360
x + 145 + x + 145 = 360 
x = 35
Therefore angle C is 35 degrees 
8 0
3 years ago
Read 2 more answers
(x – 3)(4x + 2) using the distributive property. Select the answer choice showing the correct distribution
Nataly [62]

The distributive property: a(b + c) = ab + ac

(x - 3)(4x + 2) = (x)(4x + 2) + (-3)(4x + 2)

= (x)(4x) + (x)(2) + (-3)(4x) + (-3)(2) = 4x² + 2x - 12x - 6

<h3>= 4x² - 10x - 6</h3>
5 0
3 years ago
Need help please don't know this
vesna_86 [32]
Perimeter = 2w + 2l
2(8x+2) + 2(6x + 6)
Use distributive property
16x + 4 + 12x + 12
Combine like terms
28x + 16

Solution: 28x + 16
3 0
2 years ago
Read 2 more answers
Determine the zeroes of the polynomial
Anna71 [15]

Answer:

3,7/6

Step-by-step explanation:

(\sqrt{x^2-4x+3} )+(\sqrt{x^{2} -9} )-(\sqrt{4x^2-14x+6} )\\=(\sqrt{x^2-x-3x+3} )+(\sqrt{(x^2-3^2})-(\sqrt{4x^2-2x-12x+6})\\ =(\sqrt{x(x-1)-3(x-1)} )+\sqrt{(x+3)(x-3)}-\sqrt{2x(2x-1)-6(2x-1)}  \\=\sqrt{(x-1)(x-3)}+\sqrt{(x+3)(x-3)}  -\sqrt{2(2x-1)(x-3)} \\=\sqrt{x-3} (\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} )\\

\sqrt{x-3} =0~gives~x=3\\or~\sqrt{x-1} +\sqrt{x+3} -\sqrt{2(2x-1)} =0\\or~ \sqrt{x-1} +\sqrt{x+3} =\sqrt{2(2x-1)} \\squaring\\x-1+x+3+2\sqrt{x-1} \sqrt{x+3} =2(2x-1)\\2x+2+2\sqrt{(x-1)(x+3)} =4x-2\\2\sqrt{x^2-x+3x-3} =2x-4\\\sqrt{x^2+2x-3} =x-2\\again ~squaring\\x^2+2x-3=x^2-4x+4\\\\2x+4x=4+3\\6x=7\\x=\frac{7}{6}

8 0
3 years ago
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