Answer:
185 gms o NaBr
Explanation:
Na Br mole weight = 22.989 +79.904 = <u>102.893 gm/mole</u>
1.083 x 10^24 molecules / 6.022 x 10^23 molecules / mole = <u>1.798 moles</u>
102.893 * 1.798 = 185 gms
Answer:
1) 94.0° C, 2) 34.7°C
Explanation:
1)
Q=mcΔt° =mc(t2 - t1)
2350 J = 85.0 g* 0.385 J/(g*°C) *(t2 - 22.2°C)
t2 - 22.2°C = 71.81°C
t2 = 94.0° C
2)
Q=mcΔt° =mc(t2 - t1)
- 2070 J = 75.0 g * 0.903 J/(g*°C) *(t2 -65.3°C)
t2 - 65.3°C = - 30.56°C
t2 = 34.7°C
Answer:
When silver nitrate (AgNO3) and potassium chloride (KCl) combine in their liquid state, they form two products by double displacement method.
Silver Chloride (AgCl) and Potassium Nitrate (KNO3)
The reaction is AgNO3 + KCl --- AgCl + KNO3
The precipitate formed is AgCl
Explanation:
Answer:
26.981539 u
Atomic number: 13
Symbol: Al
Electron configuration: [Ne] 3s²3p¹
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