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Yakvenalex [24]
3 years ago
13

URGENT HELP NEEDED! PLEASE ANSWER WITH EXPLANATION*

Chemistry
1 answer:
VladimirAG [237]3 years ago
6 0

Answer:

1) 94.0° C, 2) 34.7°C

Explanation:

1)

Q=mcΔt° =mc(t2 - t1)

2350 J = 85.0 g* 0.385 J/(g*°C) *(t2 - 22.2°C)

t2 - 22.2°C = 71.81°C

t2 = 94.0° C

2)

Q=mcΔt° =mc(t2 - t1)

- 2070 J = 75.0 g * 0.903 J/(g*°C) *(t2 -65.3°C)

t2 - 65.3°C =  - 30.56°C

t2 = 34.7°C

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Answer:

THE MOLARITY OF THE SOLUTION IS 3.36 MOLE/L

Explanation:

First we must understand what molarity is.

Molarity is the number of mole per unit volume of solution. In this question, 9.25 mole of H2SO4 was given in 2.75 L of solution.

Molarity is written in mole per dm3 or L.

So we can calculate the molarity:

9.25  ole of H2SO4 = 2.75 L of solution

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8 0
4 years ago
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-Dominant- [34]

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General Formulas and Concepts:

<u>Chem</u>

  • Reading a Periodic Table
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Explanation:

The Periodic Trend for 1st Ionization Energy is increasing up and to the right. That means He would have the highest I.E and therefore take the most amount of energy to remove an electron.

Potassium and Gallium are both in Period 4. Potassium is element 19 and Gallium is element 31.

Potassium's electron configuration is [Ne] 4s¹ and Gallium's electron configurations is [Ne] 4s²3d¹⁰4p¹. Since both are in Period 4, they have the same number of core e⁻. Therefore, the shielding effect is the same.

However, since Gallium is element 31, it has 31 protons compared to Potassium, which is element 19 and has 19 protons. Gallium would have a greater Zeff than Potassium as it has more protons. Therefore, the FOA between the electrons and nucleus of Ga is much stronger than that of K. Thus, Ga requires <em>more</em> energy to overcome those FOA to remove the 4p¹ e⁻. Since K has less protons, it will have a smaller Zeff and thus less FOA between the e⁻ and nucleus, requiring <em>less</em> energy to remove the 4s¹ e⁻.

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Answer:

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gayaneshka [121]

Answer:

9 is your answer

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