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3 years ago

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Which of these is not true of Bohr's model of the atom ?

2 answers:

adelina 88 [10]3 years ago

7 0

B and D are not true of Bohr's model of the atom. Bohr's model assumed that electron of a hydrogen atom travels in discrete elliptical orbits (not circular, as you have probably been taught) whose size depended on the allowed energy levels of the electron.

Molodets [167]3 years ago

6 0

Answer:

D. electrons don't exist

Explanation:

Bohr's model describes an atom as a planet and predict that electrons orbit the nucleus of the atom at a quantised energy level referred to as shells. If not quantised, then the electrons ought to spiral into the nucleus due to the attractive Coulombic forces between the them. The shells are not planar as imagined.

The model do not predicts that electrons don't exist.

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The ionic radius for Na+ is 0.097 ηm and for Cl- is 0.181 ηm, the absolute value of the charge for each ion is 1.6x10-19 C, ε_o=

Vanyuwa [196]

Answer:

B = (2.953 × 10⁻⁹⁵) N.m⁹

Explanation:

At equilibrium, where the distance between the two ions (ro) is the sum of their ionic radii, the force between the two ions is zero.

That is,

Fa + Fr = 0

Fa = - Fr

Fa = (|q₁q₂|)/(4πε₀r²)

Fr = -B/(r^n) but n = 9

Fr = -B/r⁹

(|q₁q₂|)/(4πε₀r²) = (B/r⁹)

|q₁| = |q₂| = (1.6 × 10⁻¹⁹) C

(1/4πε₀) = k = (8.99 × 10⁹) Nm²/C²

r = 0.097 + 0.181 = 0.278 nm = (2.78 × 10⁻¹⁰) m

(k|q₁q₂|)/(r²) = (B/r⁹)

(k × |q₁q₂|) = (B/r⁷)

B = (k × |q₁q₂| × r⁷)

B = [8.99 × 10⁹ × 1.6 × 10⁻¹⁹ × 1.6 × 10⁻¹⁹ × (2.78 × 10⁻¹⁰)⁷]

B = (2.953 × 10⁻⁹⁵) N.m⁹

6 0

3 years ago

shusha [124]

Use the equation for density :
Density = mass / volume
Density = 120 / 480
Density = 0.25

5 0

3 years ago

Read 2 more answers

The solubility of silver(I)phosphate at a given temperature is 1.02 g/L. Calculate the Ksp at this temperature. After you get yo

Snezhnost [94]

<u>Answer:</u> The solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

<u>Explanation:</u>

We are given:

Solubility of silver (I) phosphate = 1.02 g/L

To convert it into molar solubility, we divide the given solubility by the molar mass of silver (I) phosphate:

Molar mass of silver (I) phosphate = 418.6 g/mol

$\text{Molar solubility of silver (I) phosphate}=\frac{1.02g/L}{418.6g/mol}=2.44\times 10^{-3}mol/L$

Solubility product is defined as the product of concentration of ions present in a solution each raised to the power its stoichiometric ratio.

The chemical equation for the ionization of silver (I) phosphate follows:

$Ag_3PO_4(aq.)\rightleftharpoons 3Ag^{+}(aq.)+PO_4^{3-}(aq.)$

3s s

The expression of $K_{sp}$ for above equation follows:

$K_{sp}=(3s)^3\times s$

We are given:

$s=2.44\times 10^{-3}M$

Putting values in above expression, we get:

$K_{sp}=(3\times 2.44\times 10^{-3})^3\times (2.44\times 10^{-3})\\\\K_{sp}=9.57\times 10^{-10}$

Hence, the solubility product of silver (I) phosphate is $9.57\times 10^{-10}$

4 0

2 years ago

When you convert a measurement from SI to English, what changes? units , values , error , or resolution

Julli [10]

The answer to your question is units and values

6 0

3 years ago

Which of the following is an organic compound

mel-nik [20]

An Organic Compound is when Hydrogen and Nitrogen are bonded.

Therefore A is the answer

6 0

3 years ago

Read 2 more answers