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MAXImum [283]
3 years ago
11

Which of these is not true of Bohr's model of the atom ?

Chemistry
2 answers:
adelina 88 [10]3 years ago
7 0
B and D are not true of Bohr's model of the atom. Bohr's model assumed that electron of a hydrogen atom travels in discrete elliptical orbits (not circular, as you have probably been taught) whose size depended on the allowed energy levels of the electron.
Molodets [167]3 years ago
6 0

Answer:

D. electrons don't exist

Explanation:

Bohr's model describes an atom as a planet and predict that electrons orbit the nucleus of the atom at a quantised energy level referred to as shells. If not quantised, then the electrons ought to spiral into the nucleus due to the attractive Coulombic forces between the them. The shells are not planar as imagined.

The model do not predicts that electrons don't exist.

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An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is . The ballo
Liula [17]

The question is incomplete, here is a complete question.

An arctic weather balloon is filled with 27.8 L of helium gas inside a prep shed. The temperature inside the shed is 13 ⁰C. The balloon is then taken outside, where the temperature is -9 ⁰C. Calculate the new volume of the balloon. You may assume the pressure on the balloon stays constant at exactly 1 atm. Be sure your answer has the correct number of significant digits.

Answer : The new volume of the balloon is 25.7 L

Explanation :

Charles's Law : It is defined as the volume of the gas is directly proportional to the temperature of the gas at constant pressure and number of moles.

V\propto T

or,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1 = initial volume of gas = 27.8 L

V_2 = final volume of gas = ?

T_1 = initial temperature of gas = 13^oC=273+13=286K

T_2 = final temperature of gas = -9^oC=273+(-9)=264K

Now put all the given values in the above equation, we get:

\frac{27.8L}{286K}=\frac{V_2}{264K}

V_2=25.7L

Therefore, the new volume of the balloon is 25.7 L

3 0
2 years ago
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