For the given reaction, according to the Law of Conservation of Energy, the energy required to decompose Hcl and produce
are equal.
Answer: Option C
<u>Explanation:</u>
According to law of conservation's of energy, energy can only be transferred from reactants to product side. So in this process, it is stated that 185 kJ of energy will be needed to decompose it. So that 185 kJ of energy will be getting transferred to produce the creation of hydrogen and chloride in the product side.
So if we see from the reactants side, the energy of 185 kJ is required for decomposition of hydrogen chloride. Similarly, if we see from the product side, the 185 kJ utilized for decomposition is transferred as energy required to create hydrogen and chlorine atoms. This statement will be in accordance with the law of conservation's of energy.
From increasing atomic mass. He also made groups and periods.
Answer:
![\boxed {\tt 20.317567567568 \ mL}](https://tex.z-dn.net/?f=%5Cboxed%20%7B%5Ctt%2020.317567567568%20%5C%20mL%7D)
Explanation:
The density formula is:
![d=\frac{m}{v}](https://tex.z-dn.net/?f=d%3D%5Cfrac%7Bm%7D%7Bv%7D)
Let's rearrange the formula for
. the volume. Multiply both sides by
, then divide by
.
![d*v=\frac{m}{v}*v](https://tex.z-dn.net/?f=d%2Av%3D%5Cfrac%7Bm%7D%7Bv%7D%2Av)
![d*v=m](https://tex.z-dn.net/?f=d%2Av%3Dm)
![\frac{d*v}{d}=\frac{m}{d}](https://tex.z-dn.net/?f=%5Cfrac%7Bd%2Av%7D%7Bd%7D%3D%5Cfrac%7Bm%7D%7Bd%7D)
![v=\frac{m}{d}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7Bm%7D%7Bd%7D)
The volume can be found by dividing the mass by the density. The mass of the object is 30.07 grams and the density is 1.48 grams per milliliter.
![m= 30.07 \ g\\d= 1.48 \ g/mL](https://tex.z-dn.net/?f=m%3D%2030.07%20%5C%20g%5C%5Cd%3D%201.48%20%5C%20g%2FmL)
![v=\frac{30.07 \ g}{1.48 \ g/mL}](https://tex.z-dn.net/?f=v%3D%5Cfrac%7B30.07%20%5C%20g%7D%7B1.48%20%5C%20g%2FmL%7D)
Divide. Note, when dividing, the grams, or
will cancel out.
![v= \frac{30.07}{1.48 \ mL}](https://tex.z-dn.net/?f=v%3D%20%5Cfrac%7B30.07%7D%7B1.48%20%5C%20mL%7D)
![v=20.317567567568 \ mL](https://tex.z-dn.net/?f=v%3D20.317567567568%20%5C%20mL)
The volume of the object is 20.317567567568 milliliters.