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NemiM [27]
4 years ago
5

In order to rescue Sela's cat, her mother propped a 19 foot long ladder against a tree at a 42° angle with the ground. How

Mathematics
1 answer:
alekssr [168]4 years ago
5 0

Answer:

12.7 feet

Step-by-step explanation:

To solve this question, we use the trigonometric function of Sine

sin θ = Opposite side/Hypotenuse

θ = 42°

Hypotenuse = 19 foot ladder

Opposite side = Distance of the cat from the ground(height of the tree)= unknown

sin 42° = Opposite/19 feet

Opposite = sin 42° × 19

Opposite = 12.713481521 feet

Approximately to the nearest tenth of a foot = 12.7 feet.

Therefore, the cat was 12.7 feet above the ground.

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Given the graph of a line y=−x. Write an equation of a line which is parallel and goes through the point (8,2).
serious [3.7K]

The slope of y = -x is m = -1.  Thus, starting with the slope-intercept form y = mx + b, we substitute -1 for m, 8 for x and 2 for y, to determine the vaue of b:

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y = -x + 10.

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4 years ago
Answer the following questions using complete sentences. One word answers are not acceptable.
Len [333]

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3 0
3 years ago
4. Given point A (3, 8) and point B (-5, 1). Find the following:
Anni [7]

Answer:

a) (-1,4.5)

b)10.63 units

c)7/8

Step-by-step explanation:

a) To find this, we use the midpoint formula

(x,y) = (x1 + x2)/2 , (y1 + y2)/2

(x1,y1) = (3,8)

(x2,y2) = (-5,1)

(x,y) = (3 -5)/2 , (8 + 1)/2 = (-1, 4.5)

b) To calculate the distance D between two points, we use the formula;

D = √(x2-x1)^2 + (y2-y1)^2

D = √(-5-3)^2 + (1-8)^2

D = √(-8)^2 + (-7)^2

D = √64 + 49

D = √113

D = 10.63 units

C) We use the slope formula here

m = (y2-y1)/(x2-x1)

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6 0
3 years ago
Let a=<-4,-3,5> Find a unit vector in the same direction as having positive first coordinate.
Rashid [163]

Answer:

The value is u =  < \frac{2\sqrt{2}}{10} , \frac{3\sqrt{2}}{10} , - \frac{\sqrt{2}}{2}>

Step-by-step explanation:

From the question we are told that

The vector is a=<-4,-3,5>

Generally the unit vector is u = ay

Here y represent the y-coordinate

So

u =y

=> u =

Generally the resultant of a unit vector is 1

So

|u| = \sqrt{ (-4y)^2 + (-3y)^2 + (5y)^2} = 1

Hence

|u| = \sqrt{ 16y^2 + 9y^2 + 25y^2} =  1

Taking the square of both sides

16y^2 + 9y^2 + 25y^2 =  1

=> 50y^2 =  1

=> y =  \pm \frac{1}{\sqrt{50}}

=> y =  \pm \frac{1}{5 \sqrt{2}}

Rationalizing

=> y =  \pm \frac{\sqrt{2}}{10}

Given that the first coordinate is positive

y = - \frac{\sqrt{2}}{10}

Hence the unit vector is

u =

=> u =  < \frac{2\sqrt{2}}{10} , \frac{3\sqrt{2}}{10} , - \frac{\sqrt{2}}{2}>

4 0
3 years ago
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