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USPshnik [31]
3 years ago
11

If 22x = 23, what is the value of x? -1/2 -1/4 1/4 no solution

Mathematics
1 answer:
nlexa [21]3 years ago
6 0

Answer: x=\frac{23}{22}≈1.04

Step-by-step explanation:

You need to solve for the variable "x" to find its value.

To solve for "x" you need to apply the Division property of equality. This  states that:

If\ a=b\ then\ \frac{a}{c}=\frac{b}{c}

Then, knowing this, you can divide both sides of the equation by 22. Therefore, you get that the value of "x" is the following:

\frac{22x}{22}=\frac{23}{22}

x=\frac{23}{22}

x≈1.04

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YO please help actually been waiting for an hour and a half cuz so many trolls lol. <3 giivng brainliest, and ty in advance g
kati45 [8]

Hello!

For this problem we are given that quadrilateral ABCD is congruent to quadrilateral GJIH, meaning that all sides and angle measures will be equivalent to its corresponding side.

This means that to find x, we can look at quadrilateral GJIH's corresponding side to quadrilateral ABCD's side AD, which is side GH, which has a value of 9.

This means that 9 should also be the side length of side AD, which we're given a value of x/3.

x/3=9

Solve.

x=27

Hope this helps!

8 0
3 years ago
Read 2 more answers
In a random sample of 18 families, the average weekly food expense was $95.60 with a sample standard deviation of $22.50. Determ
shepuryov [24]

Answer:

t-distribution should be used to construct a confidence interval.

Step-by-step explanation:

We are given that a random sample of 18 families, the average weekly food expense was $95.60 with a sample standard deviation of $22.50.

We have to determine whether a normal distribution (Z values) or a t- distribution should be used or whether neither of these can be used to construct a confidence interval.

<em><u>Since in this question we are provided with;</u></em>

Sample average weekly food expense, \bar X = $95.60

Sample standard deviation, s = $22.50

Sample of families, n = 18

The distribution that we will use here to construct a confidence interval will be <u>t-distribution</u> because in the question we don't know anything about population standard deviation (\sigma) .

Normal distribution is used when we know population standard deviation (\sigma).

So, the pivotal quantity for confidence interval that will be used is One-sample t-test statistics;

                P.Q. = \frac{\bar X -\mu}{\frac{s}{\sqrt{n} } } ~ t_n_-_1

Therefore, t-distribution should be used to construct a confidence interval.

3 0
3 years ago
How would you write 3,279 is greater than 3,273
german
Here's how 3,279>3,273
6 0
3 years ago
The table represents an exponential function. A 2-column table has 4 rows. The first column is labeled x with entries 1, 2, 3, 4
GenaCL600 [577]

Answer:A. on edge

Step-by-step explanation:

Just took the quiz.

5 0
3 years ago
-3(-x+4)=5+3(x+1) please help​
Lostsunrise [7]

Answer:

No solution.

Step-by-step explanation:

Step 1: Write equation

-3(-x + 4) = 5 + 3(x + 1)

Step 2: Solve for <em>x</em>

  1. Distribute: 3x - 12 = 5 + 3x + 3
  2. Combine like terms: 3x - 12 = 3x + 8
  3. Subtract 3x on both sides: -12 ≠ 8

Here, we see that <em>x</em> has to equal no solution. No value of <em>x</em> would make the equation true.

3 0
3 years ago
Read 2 more answers
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