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2 years ago

Find the least common denominator for these two rational expressions. -8/x^2 -1/5x

Mathematics

1 answer:

stiks02 [169]2 years ago

8 0

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Find the formula for the area of the shaded region in the figure. x² = 4py ہے

Alexandra [31]

The formula for the area of the shaded region in the figure.

x² = 4py is mathematically given as

$A=\frac{8}{3} \sqrt{p h} \cdot h$

<h3>What is the formula for the area of the shaded region in the figure?</h3>

Parameters

$x^{2}=4 p y$

$y=h$

$\therefore x^{2}=4 p h \Rightarrow x=2 \sqrt{p h} \\$

Generally, the equation for the Area is mathematically given as

$& A=2 \int_{0}^{2 \sqrt{p h}}\left(h-\frac{x^{2}}{4 p}\right) d x \\\\& A=2\left(h x-\frac{x^{3}}{12 p}\right]_{0}^{2 \sqrt{p h}} \\\\& A=2\left[\left[h 2 \sqrt{p h}-\frac{1}{12 p} \cdot(2 \sqrt{p h})^{3}-0\right]\right. \\$

$&A=2\left[2 h^{3 / 2} \sqrt{p}-\frac{8(\sqrt{p})^{3}(\sqrt{h})^{3}}{12 p}-0\right] \\\\&A=2\left[2 h^{k / 2} \sqrt{p}-\frac{2}{3} \sqrt{p} \cdot h^{3 / 2}\right] \\\\&A=2 \times \frac{4 \sqrt{p} \cdot h^{3 / 2}}{3} \\\\&A=\frac{8}{3} \cdot \sqrt{p} \cdot \sqrt{h} \cdot h \\\\&A=\frac{8}{3} \sqrt{p h} \cdot h$

$A=\frac{8}{3} \sqrt{p h} \cdot h$

In conclusion, the equation for the Area is

$A=\frac{8}{3} \sqrt{p h} \cdot h$

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5 0

1 year ago

If f(x) = 2x²+2 and g(x) = x² - 1 ,find (f- g)(x).

mestny [16]

Step-by-step explanation:

(F-g) (X)

= f(x) - g(x)

(2x² + 2 )-(x²-1) =

3x²+3

4 0

2 years ago

If 4 friends have 8 apples how many will each friend get

Natalka [10]

2 because 8 divided by 4 is 2.

6 0

2 years ago

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What is the property of 42x1=42

Ira Lisetskai [31]

Identity property of multiplication

7 0

3 years ago

A tub filled with 50 quarts of water empties at a rate of 2.5 quarts per minute. let w = quarts of water left in the tub and t =

Sholpan [36]

This is a linear relationship. The slope-intercept form of the linear equation is:

$y=mx+c$

Where,

m is the rate of change (positive if increasing rate and negative if decreasing rate)
c is the y intercept, or the initial value

Rate of change is 2.5 quarts per minute (it is decreasing so m is -2.5)

Initial value is 50 quarts, so c is 50.

Plugging in the values we get $y=-2.5x+50$ .

Changing variables to w instead of y and t instead of x, gives us,

$w=50-2.5t$ . Where w is warts of water left in the tub and t is the time in minutes.

There is no viable solution when t=30 because at t=20, w=0 ( $0=50-2.5(20)$ ). It means after 20 minutes, there is no water left. So t=30 minutes doesn't make sense.

ANSWER:

Modelling equation: $w=50-2.5t$

When $t=30$ , there is no VIABLE solution

5 0

2 years ago

Read 2 more answers