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Dennis_Churaev [7]
3 years ago
9

Which letter below is NOT made only of line segments?DХМF​

Mathematics
1 answer:
MrMuchimi3 years ago
5 0

Answer:

D

Step-by-step explanation:

The letter D includes a curved line, unlike the letters X, M, and F.

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A dinner theater sold 270 tickets in 3 hours. At this rate, how many tickets will be sold in 8 hours
Sveta_85 [38]

Answer:

720 tickets in 8 hours

Step-by-step explanation:

you know that the theatre sold 270 tickets in 3 hours. you have to find the hourly rate of tickets sold. so you divide 3 into 270 and get 90. you take the hourly rate of tickets and multiply it by the 8 hours and get 720. Hope this helps!! :)

4 0
3 years ago
A boy scout has 3 meters of rope. He cuts the rope into cords on 3/5 m long. How many cords will he make?
zepelin [54]
It should be 5, i have uploaded it worked out

3 0
3 years ago
Brianna can rent a scooter for $15.00 plus $0.50 per mile.
torisob [31]

Answer:

you can say y=0.50m+15t

5 0
3 years ago
Gina has 20 groups of 10 pencils 137 are sharpened how many dual pencils does Gina have
saul85 [17]

well, I think the whole group thing is ment to distract you. Math problems can be evil like that. If she has 200 pencils. and 137 ove them a sharp, you have to subtract 137 from 200.      200-137=23 :3 she has 23 unshapened pencils.

7 0
3 years ago
Show all work to solve the equation for x. If a solution is extraneous, be sure to identify it in your final answer.
IRISSAK [1]

Answer:

There is one extraneous solution at x = 4

The only solution is x=7

Step-by-step explanation:

Given:

The equation to solve is given as:

\sqrt{x-3}+5=x

In order to solve, we will first isolate the radical part.

<em>Adding -5 on both the sides, we get:</em>

\sqrt{x-3}+5-5=x-5\\\sqrt{x-3}=x-5

<em>Now, squaring both the sides, we get:</em>

(\sqrt{x-3})^2=(x-5)^2\\\\x-3=x^2+25-10x\\\\x^2-10x-x+25+3=0\\\\x^2-11x+28=0\\\\(x-4)(x-7)=0\\\\x=4\ or\ x=7

Now, let us check whether the calculated values satisfy the equations or not.

Plug in 4 and 7 for 'x' and check the value of the equation.

At x=4,

\sqrt{4-3}+5=4\\\sqrt1+5=4\\1+5=4\\6=4

But, 6 is not equal to 4 and hence 4 is not a solution to the given equation. It is an extraneous solution for the given equation.

Now, at x=7

\sqrt{7-3}+5=7\\\sqrt4+5=7\\2+5=7\\7=7(True)

Therefore, x=7 is a solution to the equation.

Hence, there is one extraneous solution at x = 4

The only solution is x=7

6 0
4 years ago
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