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3 years ago

Which triangles (if any) can be shown to be congruent using a rotation? A) 1 and 2 B) 2 and 3 C) 1 and 3 D) none

Mathematics

1 answer:

Talja [164]3 years ago

6 0

The answer is 1 and 3.

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Of the 20 students in Emily's class 15 like chocolate cake and the rest like cheesecake how many like cheesecake and what percen

alisha [4.7K]

5 students like cheesecake because if there is 20 students in all and 15 like chocolate and the rest like cheesecake you do 20-15=5

If 5 students like cheesecake out of 20 it would be 5/20 20*5=100 just multiply by 5 5*5=25%

25% of students like cheesecake

4 0

3 years ago

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7th grade math help me please :))

Sav [38]

Answer:

no because the absolute value of -7 is 7 which is greater than the absolute value of 6 which is 6.

8 0

2 years ago

Help me with this please.<br>

Flura [38]

Answer:

Step-by-step explanation:

Points A,B ,C are all to the left of 0 so they are negative

We want a point -3 1/2

The points A and B are to the left of -3 so they are more negative than -3

A is at -5 so it cannot be -3 1/2

7 0

3 years ago

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Select whether the triangle is inscribed in the circle, circumscribed about the circle, or neither.

Ganezh [65]

Neither inscribed in the circle, nor circumscribed about it! 2 if the sides of the triangle are TANGENT to the circle, which means just touching at one point

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2 years ago

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Select all the pairs that could be reasonable approximations for the diameter and circumference of a cirlce 5 meters and 22 mete

bazaltina [42]

Answer:

Option a) circle 5 meters and 22 meters

Step-by-step explanation:

We are given the following information in the question:

A pair of diameter and the circumference is given. We have to find a correct approximations for the diameter and circumference.

a) circle 5 meters and 22 meters

$\text{Diameter} = 5\text{ meters}\\\text{Circumference} = \pi d = 3.14\times 5 = 15.7\text{ meters}$

b) 19 inches and 50 inches

$\text{Diameter} = 19\text{ inches}\\\text{Circumference} = \pi d = 3.14\times 19 = 59.66\text{ inches}$

c) 33 centimeters and 80 centimeters

$\text{Diameter} = 33\text{ centimeters}\\\text{Circumference} = \pi d = 3.14\times 33 =103.62\text{ centimeters}$

Thus, no pair gives a reasonable approximation. Only the circle with diameter 5 and circumference 22 meters have closest approximation.

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3 years ago