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iren [92.7K]
3 years ago
6

Select the best answer for the question. 1. What is 12/3 as an improper fraction?

Mathematics
1 answer:
natali 33 [55]3 years ago
6 0
Well, technically 12/3 is already in the form of an improper fraction. You could simplify it and rewrite as 4/1. An improper fraction is one where the numerator is larger than that of the denominator, rather than a part being compared to a whole, you would have essentially have many wholes.
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I need help plzz. <br><br> Dilate this by 1/3
leva [86]
For this shape there are four points. The plotted ordered pairs are:
M = (3, 9)
N = (6, 0)
O = (3, 6)
P = (-3, 0)

All you have to do is multiply the BOTH x- and y-values by 1/3 on EACH ordered pair. And if it’s easier, you can divide by 3 as well. It’s the same thing.

M = (3, 9) = (3*1/3, 9*1/3) = (1, 3)
N = (6, 0) = (6*1/3, 0*1/3) = (2, 0)
O = (3, 6) = (3*1/3, 6*1/3) = (1, 2)
P = (-3, 0) = (-3*1/3, 0*1/3) = (-1, 0)

(1, 3) , (2, 0) , (1, 2) , and (-1, 0) are your points.

8 0
3 years ago
Read 2 more answers
What is the difference between a histogram and a cumulative histogram?
diamong [38]

Answer: The answer is provided below

Step-by-step explanation:

A histogram is a diagram which consist of rectangles whereby the area is proportional to frequency of a variable and the width is equal to class interval. A histogram is a commonly used graph that is used to show frequency distributions.

The cumulative histogram is a histogram whereby the vertical axis doesn't gives only the counts for a single bin, but gives the counts for that bin and all the bins for the maller values of a response variable.

Cumulative histograms are similar to normal histograms, but the main difference is that they graph cumulative frequencies unlike histograms that graph just frequencies.

3 0
3 years ago
Question 2 of 10
UNO [17]

Answer:

9800000

Step-by-step explanation:

8 0
3 years ago
Pelomyxa palustris is an amoeba with a length of 4.9 mm.Amoeba proteus has a length of 0.7 mm.How many amoeba proteus would you
prohojiy [21]

Answer:

  21

Step-by-step explanation:

Let n represent the number we're looking for. Then ...

  n × (proteus length) = 3 × (palustris length)

  n × 0.7 mm = 3 × 4.9 mm

  n = (3 × 4.9 mm)/(0.7 mm) = 3 × 49/7 = 3 × 7

  n = 21

You would have to line up 21 amoeba proteus to equal the length of three pelomyxa palustris.

3 0
3 years ago
Identify the x-intercepts of the function below f(x)=x^2+12x+24
damaskus [11]

<u>ANSWER:  </u>

x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

<u>SOLUTION:</u>

Given, f(x)=x^{2}+12 x+24 -- eqn 1

x-intercepts of the function are the points where function touches the x-axis, which means they are zeroes of the function.

Now, let us find the zeroes using quadratic formula for f(x) = 0.

X=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Here, for (1) a = 1, b= 12 and c = 24

X=\frac{-(12) \pm \sqrt{(12)^{2}-4 \times 1 \times 24}}{2 \times 1}

\begin{array}{l}{X=\frac{-12 \pm \sqrt{144-96}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{48}}{2}} \\\\ {X=\frac{-12 \pm \sqrt{16 \times 3}}{2}} \\\\ {X=\frac{-12 \pm 4 \sqrt{3}}{2}} \\ {X=\frac{2(-6+2 \sqrt{3})}{2}, \frac{2(-6-2 \sqrt{3})}{2}} \\\\ {X=(-6+2 \sqrt{3}),(-6-2 \sqrt{3})}\end{array}

Hence the x-intercepts of  \mathrm{x}^{2}+12 \mathrm{x}+24=0 \text { are }(-6+2 \sqrt{3}),(-6-2 \sqrt{3})

8 0
3 years ago
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