Answer:
Following are the solution to the given question:
Step-by-step explanation:
Please find the complete question in the attached file.

The testing states value is:

therefor the 
Through out the above equation its values Doesn't rejects the H_0 value, and its sample value doesn't support the claim that although the configuration of its dependent variable has been infringed.
Answer:
slope: ½
y-intercept: -4½
Step-by-step explanation:
Slope: negative reciprocal of -2
-1/-2 = 1/2
y = ½x + c
-6 = ½(-3) + c
-6 = -3/2 + c
c = -6 + 3/2
c = -9/2 = -4½
Answer:
60°
Step-by-step explanation:
ABCO is a parallelogram (opposite sides are parallel).
AO is equal to the radius of the circle, so BC must also equal the radius.
CO is equal to the radius of the circle, so AB must also equal the radius.
If we draw a line from O to B, we split the parallelogram into two triangles. Since OB is equal to the radius of the circle, each triangle is an equilateral triangle. Therefore, angle A is 60°.
Answer:
The error is at step (3) .
The correct step (3) will be,

=
[by using the laws of indices]
All other steps are correct.
Step-by-step explanation:
The error is at the step (3) , because the student has tried to prove the quotient rule of logarithms by using the property i.e., 'The quotient rule of logarithm' itself , i.e. ,by assuming the property does hold before proving it. So, the proof is fallacious.
The correct step (3) will be,

=
[by using the laws of indices]
All other steps are correct.
Answer:
(-1, 5/2)
Step-by-step explanation:
That is what I got