The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles
of air. Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?
2 answers:
Answer: 99.5 g
1) Data:
molar mass, MM = 28.97 g/mol
number of moles = 3.33 moles
2) Formula:
mass in grams = number of moles × molecular mass
3) Calculations:
mass in grams = 3.33 mol × 29.87 g/mol = 99.5 g
Note that the unit mol cancel because it is in the numerator of the first factor and in the denominator of the second factor.
The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles of air.
Finally, solve (remember significant figures):
A:
99.5
⇒ 96.5
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