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navik [9.2K]
3 years ago
14

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air. Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?
Chemistry
2 answers:
Rina8888 [55]3 years ago
7 0
Answer: 99.5 g


1) Data:


molar mass, MM = 28.97 g/mol

number of moles = 3.33 moles

2) Formula: 

mass in grams = number of moles × molecular mass

3) Calculations:

mass in grams = 3.33 mol × 29.87 g/mol = 99.5 g

Note that the unit mol cancel because it is in the numerator of the first factor and in the denominator of the second factor.
TiliK225 [7]3 years ago
5 0

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles of air.

Finally, solve (remember significant figures):

A:  

99.5

⇒ 96.5


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2. Na2SiO3(s) + HF(aq) !H2SiF6(aq) + NaF(aq) + H2O (l)
Alex

Answer:

a) Na2SiO3(s) + 8HF(aq) → H2SiF6(aq) + 2NaF(aq) + 3H2O (l)

b) <u>2.40 moles HF</u>

c) <u>5.25 grams NaF</u>

<u>d)0.609 grams Na2SiO3</u>

<u>e) </u> <u>0.89 grams Na2SiO3</u>

Explanation:

Step 1: Data given

Step 2: The balanced equation

Na2SiO3(s) + 8HF(aq) → H2SiF6(aq) + 2NaF(aq) + 3H2O (l)

b) How many moles of HF are needed to react with 0.300 mol of Na2SiO3?

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 0.300 moles Na2SiO3 we'll need 8*0.300 = <u>2.40 moles HF</u>

<u />

c. How many grams of NaF form when 0.500 mol of HF reacts with excess Na2SiO3?

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 0.500 moles we'll have 0.500 / 4 = 0.125 moles NaF

Mass NaF = 0.125 moles * 41.99 g/mol

Mass NaF = <u>5.25 grams NaF</u>

<u />

d. How many grams of Na2SiO3 can react with 0.800 g of HF?

Moles HF = 0.800 grams / 20.01 g/mol

Moles HF = 0.0399 moles

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 8 moles we need 1 moles Na2SiO3 to react

For 0.0399 moles we need 0.0399/8 = 0.00499 moles Na2SiO3

Mass Na2SiO3 = 0.00499 moles * 122.06 g/mol  

Mass Na2SiO3 = <u>0.609 grams Na2SiO3</u>

Using your answer to part d-If you started with 1.5 g of Na2SiO3how many grams would be left after the reaction is complete?

Number of moles HF = 0.0399 moles

Number of moles Na2SiO3 = 1.5 grams / 122.06 g/mol = 0.0123 moles

For 1 mol Na2SiO3 we need 8 moles HF to produce 1 mol H2SiF6, 2 moles NaF and 3 moles H2O

For 8 moles we need 1 moles Na2SiO3 to react

For 0.0399 moles we need 0.0399/8 = 0.00499 moles Na2SiO3

There will remain 0.0123 - 0.00499 = 0.00731 moles  Na2SiO3

Mass Na2SiO3 remaining = 0.00731 * 122.06 g/mol = <u>0.89 grams Na2SiO3</u>

<u />

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7 0
3 years ago
Use the following words to discover a doctor's favourite element:
Dmitriy789 [7]
Metal? Copper? I don’t know I just have to answer to get my question answered, have a good day!
5 0
3 years ago
A balloon has a volume of 3.50 liters at 20.0°C. What will be the volume of the balloon at 100.0°C? Assume the pressure doesn't
Nikitich [7]

<u>Answer:</u> The volume of balloon at 100°C is 4.46 L

<u>Explanation:</u>

To calculate the final temperature of the system, we use the equation given by Charles' Law. This law states that volume of the gas is directly proportional to the temperature of the gas at constant pressure.

Mathematically,

\frac{V_1}{T_1}=\frac{V_2}{T_2}

where,

V_1\text{ and }T_1 are the initial volume and temperature of the gas.

V_2\text{ and }T_2 are the final volume and temperature of the gas.

We are given:

V_1=3.50L\\T_1=20^oC=(20+273)K=293K\\V_2=?L\\T_2=100^oC=(100+273)K=373K

Putting values in above equation, we get:

\frac{3.5L}{293K}=\frac{V_2}{373K}\\\\V_2=4.46L

Hence, the volume of balloon at 100°C is 4.46 L

5 0
3 years ago
How many moles are in 1.22 * 10^20 atoms of Si
mezya [45]

Answer:

2.03 × 10⁻⁴ moles

Explanation:

To convert atoms to moles, use Avogadro's number (6.022 × 10²³).

(1.22 × 10²⁰ atoms)/(6.022 × 10²³ atoms/mol) = 2.03 × 10⁻⁴ mol

4 0
2 years ago
Exactly 1 mol Pb(ClO2)2 contains how many moles of Pb , Cl , and O ?
Masja [62]

Answer:

For 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).

Explanation:

<u>Step 1: </u>Data given

Number of moles of Pb(ClO2)2 = 1

Since the oxidation number of Pb is 2+ and the oxidation number of ClO2 is -1

So to bind we should have <u>twice</u> ClO2

1 mole of Pb(ClO2)2 contains 1 mole of Pb; 1*<u>2</u>= 2 moles of Cl and 2*<u>2</u> = 4 moles of 0.

This means for 1 mole of Lead(II)chlorie we have 1 mole of lead (Pb), 2 moles of Chlorine (Cl) and 4 moles of oxygen (O).

7 0
3 years ago
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