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navik [9.2K]
3 years ago
14

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles

of air. Next, cancel like terms and units. Which of the following shows the correct terms and units canceled?
Chemistry
2 answers:
Rina8888 [55]3 years ago
7 0
Answer: 99.5 g


1) Data:


molar mass, MM = 28.97 g/mol

number of moles = 3.33 moles

2) Formula: 

mass in grams = number of moles × molecular mass

3) Calculations:

mass in grams = 3.33 mol × 29.87 g/mol = 99.5 g

Note that the unit mol cancel because it is in the numerator of the first factor and in the denominator of the second factor.
TiliK225 [7]3 years ago
5 0

The molecular mass of air, at standard pressure and temperature, is approximately 28.97 g/mol. Calculate the mass of 3.33 moles of air.

Finally, solve (remember significant figures):

A:  

99.5

⇒ 96.5


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A disk of radius 2.0 cm has a surface charge density of 6.3 μC/m2 on its upper face. What is the magnitude of the electric field
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the electric field at Z = 12 cm is E =   9.68 × 10³ N/C = 9.68 kN/C

Explanation:

Given: radius of disk, R = 2.0 cm = 2 × 10⁻² cm, surface charge density,σ = 6.3 μC/m² = 6.3 × 10⁻⁶ C/m², distance on central axis, z = 12 cm = 12 × 10⁻² cm.

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E = σ/ε₀(1 - \frac{z}{\sqrt{z^{2} + R^{2} }  }) = 6.3 × 10⁻⁶/8.854 × 10⁻¹²(1 - \frac{0.12}{\sqrt{0.12^{2} + 0.02^{2} } }) = 7.12 × 10⁵(1 - \frac{0.12}{0.1216}) = 7.12 × 10⁵(1 - 0.9864) = 7.12 × 10⁵ × 0.0136 = 0.0968 × 10⁵ = 9.68 × 10³ N/C = 9.68 kN/C

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