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LenaWriter [7]
3 years ago
15

Many scientists, including Joseph Priestly, hypothesized that fuels lost mass as they burned due to the loss of a substance call

ed phlogiston. Since phlogiston was missing, these fuels could not undergo any further combustion. Which of the results in the experiment above refute this hypothesis?
a. Ethanol
b. Charcoal
c. Wood
d. Mercury
Chemistry
1 answer:
DanielleElmas [232]3 years ago
6 0
<h2>D this is a lot of hour to found but its ok thank you for sharing your question i hope this help</h2>

<h3>Carry on learning:)</h3>
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The table shows the amount of radioactive element remaining in a sample over a period of time.
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Answer:

1. The half-life is 22 years.

2. 132 years

Explanation:

1. Determination of the the half-life.

The half-life of an element is the time taken for half the element to decay.

From the table given above, the original amount of the element 45 g. If we divide 45 by 2, we'll have 22.5 g as half the original amount of element.

Now, the time taken to obtain 22.5 g as shown from the table is 22 years.

Thus, the half-life the element is 22 years.

2. Determination of the time.

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Time (t) =?

Next, we shall the number of half-lives that has elapsed. This can be obtained as follow:

Original amount (N₀) = 308 g

Amount remaining (N) = 4.8125 g

Number of half-lives (n) =?

N = 1/2ⁿ × N₀

4.8125 = 1/2ⁿ × 308

Cross multiply

4.8125 × 2ⁿ = 308

Divide both side by 4.8125

2ⁿ = 308 / 4.8125

2ⁿ = 64

Express 64 in index form with 2 as the base.

2ⁿ = 2⁶

n = 6

Thus, 6 half-lives has elapsed.

Finally, we shall determine the time. This can be obtained as follow:

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Half-life (t½) = 22 years

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6 0
3 years ago
In the Hall-Heroult process, a large electric current is passed through a solution of aluminum oxide Al2O3 dissolved in molten c
gtnhenbr [62]

Answer:

1.13 × 10⁶ g

Explanation:

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The mass of aluminum produced under these conditions is:

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