1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
liraira [26]
3 years ago
5

what is a measure of the amount of matter in an object while what is a measure of the force of gravity acting on an object

Chemistry
1 answer:
masha68 [24]3 years ago
7 0
A measure for the amount of matter in an object would be grams or kilograms.
the measure of the force of gravity acting on an object would be newtons.

the amount of matter in an object is called mass.
the force of gravity acting upon an object would be called weight.
You might be interested in
Jill and Susan were absent when the instructions were given for the lab investigation. They gathered their materials and watched
MrRissso [65]
Jill and Susan violated safety procedures by not properly listening and/or reading over the instructions to know all the materials, steps, and equipment they need for the lab. Hope this helps!
6 0
3 years ago
Read 2 more answers
What do all four animals have in common? cat worm spider crab
Free_Kalibri [48]
<span>They are composed of cells</span>
4 0
3 years ago
What is the chemical process of breaking down food and realeasing energy?
Sergeu [11.5K]
This  process is called aerobic respiration.
5 0
3 years ago
C3H8(g) + 5 O2(g) → 3 CO2(g) + 4 H2O(l)
stiv31 [10]

¹/3 C3H8(g) + ⁵/3 O2(g)

Explanation:

The coefficient before every molecule is representative of the number of moles. We can represent it in ration form so as to calculate the question;

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(l) means;

For every 1 mole of C₃H₈(g) and 5 moles of  O₂(g) produces  3 moles of  CO₂(g) and 4 moles of H₂O(l).

Therefore to produce 1.00 mole of CO₂(g);

We represent it in ratio;

C₃H₈(g) : CO₂(g)

1  :     3

What about ;

? (x)   :  1

We cross multiply;

3x = 1 * 1

X = 1/3

We evaluate the same for O₂;

O₂(g) : CO₂(g)

5 :     3

What about

? (x) :     1

3x = 5 * 1

x = 5/3

Learn More:

For more on evaluating moles in chemical reactions check out;

brainly.com/question/13967925

brainly.com/question/13969737

#LearnWithBrainly

7 0
3 years ago
A student with an unknown code of Q3A conducts a qualitative analysis of her unknown. Her results indicated the formation of a y
insens350 [35]

Answer:

Grey precipitate implies the presence of silver ions

Yellow precipitate implies the presence of lead II ions

Explanation:

Qualitative analysis provides us a quick method of identifying ions present in a sample by chemical reactions involving simple reagents. Precipitates having a unique colour is formed. The identity of ions in the sample is deduced from the colour of precipitate obtained when particular reagents are added.

In the question, a precipitate containing silver ions upon standing turn into grey colour. Similarly, lead II ions give a yellow precipitate.

6 0
3 years ago
Other questions:
  • How many valenence electons does sodium have?
    6·2 answers
  • The force that one surface exerts on another when the 2 rub against each other is called
    6·2 answers
  • Calculation of NCl3
    6·1 answer
  • Write the acid-base reaction where hydrogen carbonate is the acid and water is the base.
    9·1 answer
  • How much energy must be supplied to break a single 21Ne nucleus into separated protons and neutrons if the nucleus has a mass of
    6·1 answer
  • To use the gas law constant R = 0.0821, the unit for temperature should be Kelvin and the unit for volume should be milliliters.
    8·2 answers
  • How can you verify that metals conduct electricity and explain​
    12·1 answer
  • Please help me with this in the picture I need 8 thing wrong and 8 what should they do right
    12·1 answer
  • In your OWN words explain how season are formed
    7·2 answers
  • What common substance can be used to neutralize a spilled acid.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!