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Maru [420]
3 years ago
6

Thomas purchased a used vehicle that depreciates under a straight-line

Mathematics
1 answer:
zalisa [80]3 years ago
6 0

Option B:

$1300

Solution:

Given initial value = $7000, salvage value = %500, time = 5 years

Let the value of the vehicle be described by the equation

V = a + bx – – – – – (1)

where x =  number of years since purchase, a and b are constants.

When x = 0, V = $7000

a + b × 0 = 7000

⇒ a + 0 =7000

⇒ a = 7000

When x = 5, V = $500. Therefore

7000 + 5b = 500

5b = 500 – 7000

5b = –6500

$b=\frac{-6500}{5}=1300

The equation is

V = 7000 – 1300x

The slope of this equation is the depreciation rate.

Here slope is 1300.

Option B is the correct answer.

Hence $1300 depreciation per year.

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