Well, we can input both variables to check and see if the numbers hold.
-691 = -51(-15) - 74
-691 = 765-64
-691 = 701
(-15, -691) does not make the equation true.
Answer:
3.48cm³ (approximated)
Step-by-step explanation:
The maximum water that bowl can hold = The volume of the bowl

Radius is half of diameter.
<u>Given</u> -
<em>From</em><em> </em><em>the</em><em> </em><em>given</em><em> </em><em>data</em><em> </em><em>we</em><em> </em><em>can</em><em> </em><em>derive </em><em>that</em><em> </em><em>the</em><em> </em><em>radius</em><em> </em><em>of</em><em> </em><em>the</em><em> </em><em>hemispheri</em><em>cal</em><em> </em><em>bowl</em><em> </em><em>is</em><em> </em><em>5</em><em>c</em><em>m</em><em> </em><em>(</em><em>1</em><em>0</em><em>/</em><em>2</em><em>)</em>
Putting the known values into the formula to get the value of the volume of bowl :

= 3.48888cm³
= 3.48cm³
<span>When 10 grams of copper and 10 grams of iodine are mixed, what is the
theoretical yield of copper I iodide?</span>
2Cu + I2 → 2CuI
<span>30 g15 g7.5 g20 g</span>
Two figures are similar if they have the same shape but not necessarily the same size although they are the same shape they are different sizes