by the double angle identity for sine. Move everything to one side and factor out the cosine term.
Now the zero product property tells us that there are two cases where this is true,
In the first equation, cosine becomes zero whenever its argument is an odd integer multiple of
, so
where
![n[/tex ]is any integer.\\Meanwhile,\\[tex]10\sin x-3=0\implies\sin x=\dfrac3{10}](https://tex.z-dn.net/?f=n%5B%2Ftex%20%5Dis%20any%20integer.%5C%5CMeanwhile%2C%5C%5C%5Btex%5D10%5Csin%20x-3%3D0%5Cimplies%5Csin%20x%3D%5Cdfrac3%7B10%7D)
which occurs twice in the interval
for
and
. More generally, if you think of
as a point on the unit circle, this occurs whenever
also completes a full revolution about the origin. This means for any integer
, the general solution in this case would be
and
.
Answer:
1. 1.99x ≤ 25
2. 2.49x ≤ 25
3. cx ≤ 25
Step-by-step explanation:
1. The budget of Han to buy Grape is $25.
Now, if he buys x pounds of grapes at the rate of $1.99 per pound, then the inequality that represents the number of pounds of grapes that Han can buy will be given by
1.99x ≤ 25 (Answer)
2. The budget of Han to buy Grape is $25.
Now, if he buys x pounds of grapes at the rate of $2.49 per pound, then the inequality that represents the number of pounds of grapes that Han can buy will be given by
2.49x ≤ 25 (Answer)
3. The budget of Han to buy Grape is $25.
Now, if he buys x pounds of grapes at the rate of $c per pound, then the inequality that represents the number of pounds of grapes that Han can buy will be given by
cx ≤ 25 (Answer)
The information given is sufficient for this proof .
Slope of a line passing through x1 ,y1) and ( x2,y2) is given by the formula :
M = ( y2 - y1)/ ( x2-x1)
________________________________
Let us start finding the slope of line PQ
the given points are ( a,b) and ( c,d)
using the slope formula we get :
slope of line PQ = m= ( d-b) /( c-a)
Let us now try finidng slope of the another line P'Q'
It is passing through ( -b ,a) and (-d,c)
using the formula we get slope of P'Q' = m' = ( c-a) /( -d - -b)
m'= ( c-a) /( -d+b)
m'= ( c-a) / -( b-d Let us find the product of m and m' :
( d-b ) * ( c-a)
----------- ------------ = -1
(c-a) - ( b-d)
Because we got product of m and m' = -1 hence proved product of perpendicular lines are negative reciprocal of each other .
Answer:
(y2 -y1) / (x2 - x1)
Step-by-step explanation:
use that formula. The answer should be -3/0 which doesn't make sense. Are you sure you have your x values correct? Since in that case it would be a straight line and the equation for that would be x = 6 since it is a straight line up with no y intercept.
Hope that helped
