Question

What is the range of the function y = RootIndex 3 StartRoot x + 8 EndRoot?

Answer 1

Answer:

- ∞ < y < ∞

Step-by-step explanation:

The given function is, $y = \sqrt[3]{x + 8}$.

Now, the origin function of this above function is, $y = \sqrt[3]{x}$ which has real y-values as output for all real x-values input.

Hence, the function $y = \sqrt[3]{x + 8}$ will ba valid for all real values of x and will have real y-value corresponding to each x-value.

Therefore, the range of this function i.e. the y-value of this function will be  

- ∞ < y < ∞. (Answer)

Answer 2

Answer:

- ∞ < y < ∞

On edge