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jenyasd209 [6]
3 years ago
12

At a depth of 10.9 km, the Challenger Deep in the Marianas Trench of the Pacific Ocean is the deepest site in any ocean. Yet, in

1960, Donald Walsh and Jacques Piccard reached the Challenger Deep in the bathyscaph Trieste. Assuming that seawater has a uniform density of 1024 kg/m3, approximate the hydrostatic pressure (in atmospheres) that the Trieste had to withstand.
Physics
1 answer:
bearhunter [10]3 years ago
8 0

Answer:

P = 1.09 \times 10^8 Pa

Explanation:

As we know that the pressure inside the liquid level is given as

P = \rho g h + P_o

here we have

\rho = 1024 kg/m^3

h = 10.9 km

also we know that

P_o = 1.01 \times 10^5 Pa

now we have

P = (1.01 \times 10^5) + (1024)(9.81)(10.9 \times 10^3)

P = 1.09 \times 10^8 Pa

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3 years ago
PLEASE HELP!!!!
andrew11 [14]
0.304 cm I think - let me check
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All the following statements about DC current are true except:
trapecia [35]

Answer:

Is considered as not as dangerous as AC

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At a carnival, you can try to ring a bell by striking a target with a 8.91-kg hammer. In response, a 0.411-kg metal piece is sen
astraxan [27]

Answer:

4 m/s

Explanation:

M = mass of the hammer = 8.91 kg

m = mass of the metal piece = 0.411 kg

h = height gained by the metal piece = 3.88 m

Potential energy gained by the metal piece is given as

PE = mgh

PE = (0.411) (9.8) (3.88)

PE = 15.6 J

KE = Kinetic energy of the hammer

Given that :

Potential energy of metal piece = (0.219) Kinetic energy of the hammer

PE = (0.219) KE

15.6 = (0.219) KE

KE = 71.2 J

v = speed of hammer

Kinetic energy of hammer is given as

KE = (0.5) M v²

71.2 = (0.5) (8.91) v²

v = 4 m/s

5 0
3 years ago
A roller coaster is at the top of a 102 m hill and a mass of 120 kg. The coaster (at this
dybincka [34]
  • Height=h=102m
  • Mass=m=120g
  • Acceleration due to gravity=g=10m/s^2

\\ \sf\longmapsto P.E=mgh

  • P E means potential energy

\\ \sf\longmapsto P.E=102(120)(10)

\\ \sf\longmapsto P.E=122400J

7 0
3 years ago
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