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meriva
3 years ago
14

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 350 newtons stretches a sprin

g 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
Physics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

Explanation:

350 N force stretches the spring by 30 cm

spring constant K = 350 / 0.30 = (350 / 0.3) N / m

To calculate work done by a spring force we proceed as follows

spring force when the spring is stretched by x = Kx

This force is variable so work done by it can be calculated by integration

Work done by it in stretching from x₁ to x₂

W = ∫ F dx

= ∫ Kx dx with limit from x₁ to x ₂

= 1/2 K ( x₂² - x₁² )

Putting the given values of x₁ = 0.50 m , x₂ = 0.8 m

Work done

= 1/2 x (350 / 0.3)x ( 0.80² - 0.50² )

= 227.50 J

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fredd [130]

Answer:

The answer is letter B, absorb.

Explanation:

Heat travels through three different ways: radiation,conduction and convection.

Radiation- this happens when heat moves as energy waves (infrared waves) directly from its source to something.

Conduction- heat passes directly from one object to another through the touching of surfaces.

Convection- this occurs when warmer areas of a liquid or gas rise to cooler areas in the liquid or gas.

The transfer of heat in the situation above is an example of "thermal radiation." The campfire carries light energy through the fire. These consists of electromagnetic waves (most of these are infrared light). These waves (radiation) carry energy, which is then converted to heat once it hits another object that absorbs it. In the case above, once the hands absorbs the energy, it then warms up. This happened because the hands are placed <u><em>near the campfire.</em></u> Placing the hands near the campfire is important because air is a poor thermal conductor.

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4 years ago
A car slams on the brakes to stop. The road pushes back up on the car with a normal force of 12,750 N and friction from the brak
ivann1987 [24]

Answer:

\displaystyle \mu_d=0.75

Explanation:

Coefficients of Friction

Objects in physical contact produce friction which usually manifests as thermal energy being dissipated in the surface where the objects are interacting. It's usually harder to start to move an object from rest, that keeps moving it at a constant speed on the same surface. That is why there are two different coefficients of friction: the static and the dynamic. As mentioned, the static coefficient \mu_s is greater than the dynamic coefficient \mu_d. The car is already moving and is attempting to stop. The coefficient of friction is defined as

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\displaystyle \mu_d=\frac{9,560\ N}{12,750\ N}

\displaystyle \boxed{\mu_d=0.75}

The coefficient of friction is dimensionless (doesn't have any units)

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