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meriva
2 years ago
14

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 350 newtons stretches a sprin

g 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
Physics
1 answer:
Bingel [31]2 years ago
5 0

Answer:

Explanation:

350 N force stretches the spring by 30 cm

spring constant K = 350 / 0.30 = (350 / 0.3) N / m

To calculate work done by a spring force we proceed as follows

spring force when the spring is stretched by x = Kx

This force is variable so work done by it can be calculated by integration

Work done by it in stretching from x₁ to x₂

W = ∫ F dx

= ∫ Kx dx with limit from x₁ to x ₂

= 1/2 K ( x₂² - x₁² )

Putting the given values of x₁ = 0.50 m , x₂ = 0.8 m

Work done

= 1/2 x (350 / 0.3)x ( 0.80² - 0.50² )

= 227.50 J

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Cerrena [4.2K]

Explanation:

average speed = total distance travelled / total time travelled

time to travel the first 6km: 6 / 50 = 3/25 (h)

time to travel the next 6km: 6 / 90 = 1/15 (h)

[I think there's problem in the question 'cause 900km/h sounds impossible for normal person to travel in normal condition]

The total time: 3/25 + 1/15 = 14/75 (h)

Average speed over the 12 km drive will be:

\frac{12}{ \frac{14}{75} }  =  \frac{450}{7}  = 64.3 \: km{h}^{ - 1}

8 0
2 years ago
A point charge with a charge q1 = 4.00 μC is held stationary at the origin. A second point charge with a charge q2 = -4.10 μC mo
GrogVix [38]

Answer:

W = -0.480 J

Explanation:

given,

q₁ = 4 μC

q₂ = -4.10 μC

W = kq_1q_2(\dfrac{1}{a}+\dfrac{1}{b})

b = \sqrt{(0.27-0)^2+(0.27-0)^2}

b = 0.381

k = 8.99 × 10⁹ Nm²/C²

W = 8.99\times 10^9\times 4\times 10^{-6}\times (-4.1 \times 10^{-6})(\dfrac{1}{0.17}+\dfrac{1}{0.381})

W = [-147.436\times (5.88-2.62)\times 10^{-3}]J

W = -0.480 J

Work done by the electric force W = -0.480 J

4 0
2 years ago
Juan and Kuri are on a carousel. Juan is closer to the center of the carousel than Kuri. Which statement describes their tangent
Licemer1 [7]

Answer:

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

Explanation:

Since Juan is closer to the center and Kuri is away from the center so we can say that Juan will move smaller distance in one complete revolution

As we know that the distance moved in one revolution is given as

d = 2\pi r

also the time period of revolution for both will remain same as they move with the time period of carousel

Now we can say that the speed is given as

v = \frac{2\pi r}{T}

so Juan will have less tangential speed. so correct answer will be

Juan and Kuri complete one revolution in the same time, but Juan travels a shorter distance and has a lower speed.

6 0
3 years ago
Read 2 more answers
A 40 kg person sits on top of a 400 kg rock. What is the person’s weight? 390 N
algol13

The weight of the person is given by:

W = mg

W = weight, m = mass, g = gravitational acceleration

Given values:

m = 40kg, g = 9.81m/s²

Plug in and solve for W:

W = 40(9.81)

W = 390N

7 0
3 years ago
Explain how the fountain pen is filled up with ink​
Leno4ka [110]

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8 0
2 years ago
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