1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
meriva
3 years ago
14

Use Hooke's Law to determine the work done by the variable force in the spring problem. A force of 350 newtons stretches a sprin

g 30 centimeters. How much work is done in stretching the spring from 50 centimeters to 80 centimeters
Physics
1 answer:
Bingel [31]3 years ago
5 0

Answer:

Explanation:

350 N force stretches the spring by 30 cm

spring constant K = 350 / 0.30 = (350 / 0.3) N / m

To calculate work done by a spring force we proceed as follows

spring force when the spring is stretched by x = Kx

This force is variable so work done by it can be calculated by integration

Work done by it in stretching from x₁ to x₂

W = ∫ F dx

= ∫ Kx dx with limit from x₁ to x ₂

= 1/2 K ( x₂² - x₁² )

Putting the given values of x₁ = 0.50 m , x₂ = 0.8 m

Work done

= 1/2 x (350 / 0.3)x ( 0.80² - 0.50² )

= 227.50 J

You might be interested in
What is any factor of an experiment that is not changed called? control, dependent variable ,independent variable
Softa [21]
A control is the factor which is not changed 
5 0
3 years ago
Read 2 more answers
Mirage is due to...
Irina18 [472]
<span>Mirage is due to (A). unequal heating of different parts of the atmosphere,
because that produces unequal density of different parts of the atmosphere,
which bends the light.
</span>
3 0
4 years ago
A circular loop of wire of cross-sectional area 0.12 m2 consists of 200 turns, each carrying 0.50 A. It is placed in a magnetic
defon

Answer:

0.52 Nm

Explanation:

A = 0.12 m^2, N = 200, i = 0.5 A, B = 0.050 T

Angle between the plane of loop and magnetic field = 30 Degree

Angle between the normal of loop and the magnetic field = 90 - 30 = 60 degree

θ = 60°

Torque = N i A B Sinθ

Torque = 200 x 0.5 x 0.12 x 0.050 x Sin 60

Torque = 0.52 Nm

4 0
3 years ago
Which of the following is not a reason fluorescent lamps are advantages over incandescent lamps?
iren2701 [21]

It’s because flourecent lights operate at higher temperatures than incadecent lights.

3 0
3 years ago
A voltage V is applied to the primary coil of a step-up transformer with a 3:1 ratio of turns between its primary and secondary
Snezhnost [94]

Explanation:

Let N_p\ and\ N_s are the number of turns in primary and secondary coil of the transformer such that,

\dfrac{N_p}{N_s}=\dfrac{1}{3}

A resistor R connected to the secondary dissipates a power P_s=100\ W

For a transformer, \dfrac{N_s}{N_p}=\dfrac{V_s}{V_p}

V_s=(\dfrac{N_s}{N_p})V_p

V_s=3V_p...............(1)

The power dissipated through the secondary coil is :

P_s=\dfrac{V_s^2}{R}

100\ W=\dfrac{V_s^2}{R}

V_p^2=\dfrac{100R}{9}.............(2)

Let N_p'\ and\ N_s' are the new number of turns in primary and secondary coil of the transformer such that,

\dfrac{N_p'}{N_s'}=\dfrac{1}{24}

New voltage is :

V_s'=(\dfrac{N_s'}{N_p'})V_p'

V_s'=24V_p...............(3)

So, new power dissipated is P_s'

P_s'=\dfrac{V_s'^2}{R}

P_s'=\dfrac{(24V_p)^2}{R}

P_s'=24^2\times \dfrac{(V_p)^2}{R}

P_s'=24^2\times \dfrac{(\dfrac{100R}{9})}{R}

P_s'=6400\ Watts

So, the new power dissipated by the same resistor is 6400 watts. Hence, this is the required solution.

3 0
3 years ago
Other questions:
  • (a) At a certain instant, a particle-like object is acted on by a force F = (5.0 N) i hat - (2.0 N) j + (8.0 N) k while the obje
    10·1 answer
  • 4. Jimmy dropped a 10 kg bowling ball from a building that is 25 meters high.
    9·1 answer
  • What's faster a slow car or a fast feather?​
    9·2 answers
  • A wave is a:
    7·1 answer
  • Two cars of the same mass collide at an intersection. Just before the collision, one car is traveling east at 80.0 km/h and the
    6·1 answer
  • Pls help me quick im doing a quiz
    9·2 answers
  • What type of circuit is pictured?<br> O Parallel Circuit<br> Series Circuit
    13·2 answers
  • What is the net force on a car with a mass of 1000 kg if its<br> acceleration is 35 m/s^2?
    8·1 answer
  • Example of an object that has pressure energy
    9·1 answer
  • You ride your bike north for 100 m at a constant speed of 5 m/Your acceleration is…
    15·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!